The aim of this experiment is to find the concentration of a sample of limewater solution in g dm3.

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Plan
The aim of this experiment is to find the concentration of a sample of limewater solution in g dm
3. I am required to design my own experiment and choose a range of appropriate equipment and apparatus. I am provided with 250 cm3 of limewater, which has been made such that it contains approximately 1g/dm3 of calcium hydroxide. Also available is hydrochloric acid which has a concentration of 2.00 mol dm3, this concentration is too much though so it is necessary to dilute it.

The apparatus, equipment and chemicals that I will use are as follows: -
1) Pipette 25cm
3
2) Volumetric flask 500cm
3
3) Conical flask 250cm
3
4) Burette
5) White tile
6) Clamp and stand
7) Indicator (methyl orange)
8) Limewater (250cm
3 with approximately 1g/dm3 of calcium hydroxide)
9) Hydrochloric acid- standard solution (conc. 2.00 mol/dm
3)
10) Distilled water

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Slaked lime dissolved in water is called limewater.

Quicklime + Water -> Slaked lime
CaO(s) + H2O(l) -> Ca(OH)2(s)

Calcium oxide reacts violently with water to produce calcium hydroxide (slaked lime). Addition of further water to Calcium hydroxide produces the saturated aqueous solution known as Limewater. In the experiment it is necessary to react the Hydrochloric acid with the Limewater in order to establish the concentration of the limewater.

Acid + Metal Hydroxide -> Salt + Water
The balanced equation that takes place is:
Limewater + Hydrochloric acid -> Calcium chloride + Water + Hydrogen
Ca(OH)2(aq) + 2HCl ? CaCl2 + 2H2O

        

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