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To find the empirical formula of magnesium oxide

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Aim: - Experiment A- to find the empirical formula of magnesium oxide Experiment B - to find the equation for the reaction between hydrochloric acid & magnesium Health and Safety:- Safety goggles and lab coats should always be worn when working in the lab to protect against any spillage (hydrochloric acid) as well to protect again any glass that my break or fly around the lab. Keep the gases always from any naked flame, as hydrogen is flammable. Do not look directly at the burning magnesium nor inhale smoke produced when the magnesium is burned as this can be dangerous should any spitting of the contents occur. The handing of the crucible and crucible lid should be done using tongs as it will be extremely hot from the bunsen. Experiment A: Materials & Apparatus: -A 1 x Crucible 1 x lid 1 x 10cm magnesium ribbon 1 x small strip ...read more.


Results:-A Items/Elements Mass/g Mass of crucible +lid 29.760g Mass of crucible + lid + magnesium 29.860g Mass of crucible +lid+ magnesium oxide 29.910g Mass of magnesium 0.100g Mass of magniesium oxide 0.150g Mass of oxygen combined with magnesium 0.050g Mg O Mass/g .100 .050 m/gmol-1 24.3 16 n/mol 0.100 = 0.004115226 24.3 4.115226x10-3 0.050 =0.003125 16 3.125x10-3 Simplest form of magnesium oxide Mg4O3 Evaluation:- A The results for this experiment were not as expected. The actual simplest form of magnesium oxide is MgO There are a few reasons why the results of this experiment show a 25 % error and different results than originally anticipated. As the crucible lid was lifted too much of the smoke within the crucible may have escaped, thus the amount of magnesium/ oxygen bond would have been lowered. ...read more.


As the vapour rose into the gas syringe, volume increased. This reaction took approximately 2 minutes to complete until there was nothing of the metallic coil remaining. Results:-B Mg +2HCl ???gCl2 + H2 1m 1m n = volume collected (hydrogen) molar volume n = 82.5 cm3 = 0.0034372 24,000 or 3.4372x10-3 Mass of Mg n = m M n = 0.080 g = 0.003292181 24.3 g or 3.292181x10-3 Ratio 1 : 1 Ionic Charges: magnesium Mg 2+ hydrogen H 2+ cloride Cl - Evaluation:- B This experiment was very successful, as the 1: 1 ratio shows a correct figure. However, there of course is room for error, as there appeared to be 2% error in the calculations. The reason this may have occurred could be, as there was an immediate reaction once the magnesium was dropped in the hydrochloric acid, the bung may not have been replaced quick enough, thus any smoke created that the onset of the experiment may have escape. ...read more.

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