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To investigate and understand the rates of enzyme activity using five different concentrations of catalyse on a potato as an example.

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Introduction

Biology Coursework Investigating Catalyse Activity Chris Weeks 10Y3 Aim To investigate and understand the rates of enzyme activity using five different concentrations of catalyse on a potato as an example. Research In order to understand and carry out the investigation correctly, I have researched material appropriate to it. * Starch, proteins and fats are large, insoluble food molecules. * Even after the teeth have torn them, and the stomach has churned them, they are still too big and insoluble to pass through the blood stream. * They are broken down using enzymes. * Enzymes are specific, meaning they fit the substrate. * They are also catalysts and speed up the rate of reaction. * In digestion there are three important enzymes. Food Group Enzyme Building Blocks Proteins Protease Amino acids Carbohydrates Carbohydrase Sugars Fats (Lipids) Lipase Fatty acids and Glycerol * The building blocks are what the Food group are made up of. * Starch is broken down into glucose in the mouth and small intestine. * Proteins are broken down into amino acids in the stomach and small intestine. * Fats are broken down into fatty acids and Glycerol in the small intestine. * Most enzymes break substances down but some synthesize substances. * Enzymes are non-living. * They have an optimum pH and temperature. * Hydrogen peroxide will breakdown to oxygen and water in the presence of Catalyse. * The reaction will increase with the increasing enzyme concentration when molecules of hydrogen peroxide are more freely available. ...read more.

Middle

* Cut out ten different pieces of potato so they are the same shape and volume. * Put one of the five concentrations of H2O2 into the conical glass and put three discs of potato in. * Leave for three minutes. * The reaction will produce oxygen (O2), which shall travel through the delivery tube at the top of the conical glass. * The oxygen shall collect in the gas burette and cause the amount of water in the test tube to go down. * Record the amount of oxygen collected. * Repeat the experiment three times with each different concentration of H2O2. Prediction Using the information from my research and preliminary work I have made the following prediction. Hydrogen peroxide will breakdown to oxygen and water in the presence of Catalyse. This means the reaction will increase with the increasing enzyme concentration, as molecules of hydrogen peroxide are freely available. However, when molecules of the substrate are in short supply, the increase in rate of reaction is limited and will have little effect. Therefore the higher the concentration of H2O2, the greater the amount of oxygen given off, as there is a more violent reaction. Results On the following page I have displayed my results in the form of a table and graphs. NOTE: On my first test for 30% concentration, the result was too far out from the others so I have done the test again. ...read more.

Conclusion

Some factors, which I would like to investigate, are: * The increase between two concentration averages in terms of oxygen released. This would be interesting to investigate if you had the correct equipment as you could see whether it the amount of oxygen released between two concentration averages goes up in a steady pattern. (E.g. 10%=7, 20%=10 so increase is of 3). * Whether the amount of enzyme affects the amount of oxygen released. * To use different food substances instead of potato to see whether this makes any change in the results. From my experiment I do believe that I have enough results and understanding to complete my aim, which was: "To investigate and understand the rates of enzyme activity using five different concentrations of catalyse on a potato as an example." I believe I have investigated the rates of enzyme activity well and got suitable results and understanding to confirm my prediction and draw a conclusion, which is: "Hydrogen peroxide will breakdown into oxygen and water in the presence of Catalyse. The reaction will increase if the concentration of the enzyme is increased, as molecules of hydrogen peroxide are more freely available. However, when molecules of the substrate are in short supply, the increase in rate of reaction is limited and will not have a great effect. To summarize, the higher the concentration of H2O2, the greater the amount of oxygen given off, as there is a more violent reaction" This piece of coursework was on investigating and understanding the rates of enzyme activity using catalyse as an example. This has been written by Chris Weeks from 101A. ...read more.

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