To see what factors affect the rate of reaction between Sodium thiosulphate and Hydrochloric acid

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To see what factors affect the rate of reaction between  Sodium thiosulphate and Hydrochloric acid

Introduction:

 

Sodium thiosulphate and hydrochloric acid react slowly to form a white/cream precipitate that makes the solution opaque. This reaction is not immediate, but gradually the white precipitate (which is sulphur) prevents you from seeing though the beaker to the surface of the bench.  

Na2s2o3   +  2HCL                          2NaCl  +  SO2  +  S  +  H2O  

The reaction between the sodium thiosulphate and the hydrochloric acid relies on successful collisions between these two reactants. A successful collision needs three important conditions to be satisfied: -

1) The reactant molecules must collide with each other.        

2) The molecules must collide with the correct alignment.

3) The molecules must collide with enough energy to overcome the activation energy.

This graph shows the energy needed for the activation energy as the reaction continues. After the activation energy is satisfied energy is given out and the reaction ends with a lower point of energy.

When I mention successful collision these three conditions are being satisfied.

Variables:

Concentration of reactant

When you increase the concentration of sodium thiosulphate you increase the number of reactant molecules per unit volume, increasing the chance of particles colliding successfully and in turn increasing the frequency of collisions thus increasing the rate of reaction. When you double the concentration, you double the chance of a collision and double the frequency thus doubling the frequency. The rate doubles when the concentration of the reactants doubles, thus concentration is proportional to rate of reaction.

Temperature

As you increase the temperature the more energy the molecules have, thus they move faster and collide more frequently. Also the collision has greater energy thus more easily meeting the activation energy, and increasing the rate of reaction.

Surface area of the reactants

Surface area really only affects the rate of a reaction when the reactants are solids, in this experiment we are dealing with liquids. However in a reaction concerning solids the surface area affects the rate of reaction as there are more molecules of the compound exposed to the reactant thus more chances of a successful collision which break the bonds, and cause a reaction. Thus as surface area increases so does rate of reaction.

Catalysts

Catalysts reduce the initial energy to break bonds thus more successful collisions can be made, as it is easier for bonds to be broken thus increasing the rate of the reaction. They do this by offering a route of lower energy for the reaction without being used up and increasing the rate of reaction. Catalysts help reactions to take place at very low temperatures.  

Volume of the reactants

The greater the volume of the solution, the greater the depth of the solution thus greater the cloudiness of the precipitate is in the beaker and the harder it is to see through the precipitate compared to a smaller volume where it is much easier to see through the precipitate. Thus the greater the volume the greater the length of time judged the reaction over, thus this could be an unfair test if the volume was changed.

The variable I have chose to investigate is the concentration of the reactant sodium thiosulphate.

I will keep the other variables constant thus maintaining a fair test by doing the following:

  • Temperature by doing the experiment in the laboratory where the environment has a stable temperature, and I can monitor any changes of temperature.
  • Catalysts by making sure none are involved in the experiment.
  • Surface area of the reactants, no need to control this variable as this is a reaction of liquids, perhaps stirring the reactants once at the beginning so all the reactant molecules are in contact with each other.
  • Volume will be kept constant so as we change the concentration of the sodium thiosulphate we dilute it with water, so the volume will always be the same. We also will maintain the volume of the hydrochloric acid at 10 ml
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Output variable

Time taken to complete reaction

I will measure the amount of time taken for the reaction to finish using a stop watch. To find the rate from the time simply inverse the time value (i.e. 1/time)

Prediction

I predict as I increase the concentration of sodium thiosulphate you increase the number of reactant molecules per unit volume, increasing the chance of particles colliding successfully and in turn increasing the frequency of collisions thus increasing the rate of reaction. When you double the concentration, you double the chance of a ...

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