• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Aim: To investigate the reaction between sodium bicarbonate powder and ethanoic acid and discover the concept of limiting reagents.

Extracts from this document...

Introduction

´╗┐Introduction Aim: To investigate the reaction between sodium bicarbonate powder and ethanoic acid and discover the concept of limiting reagents. Variables Independent: Mass of sodium bicarbonate (NaHCO3) Dependent: Volume of carbon dioxide gas (CO2) Controlled: Ethanoic Acid (CH3COOH) Chemical Reaction NaHCO3 + CH3COOH = CH3COONa + H2O + CO2 Raw data table Mass of NaHCO3/g Volume of CO2 1st Trial (cm3 ) /+ 1 Volume of CO2 2nd Trial (cm3 ) /+ 1 Volume of CO2 3rd Trial (cm3 ) /+ 1 0.30 83 78 78 0.50 128 132 134 0.70 152 154 152 0.90 154 150 152 1.10 154 153 154 1.30 157 153 153 Qualitative observations As conical flask is swirled, tube containing NaHCO3 falls into the ethanoic solution. Large bubbles appear and the solution produces white foam. After a few minutes, bubbles stop appearing and solution in the conical flask turns clear. ...read more.

Middle

1mol = 0.006285mol + 0.00004 *used the average value out of these groups, uncertainty derived using residuals Grams of CH3COOH = 0.006285 + 0.00004 mol 60.5 = 0.3802 + 0.003g n(CH3COOH) = = =0.006331 + 0.00004 mol of CH3COOH Theoretically, 0.006331 + 0.00004 mol of CH3COOH would react with 0.006331 + 0.00004 mol of NaHCO3 , because the ratio is 1:1. But, this may not be the case in our experiment, therefore we need to find the number of moles of NaHCO3 n(NaHCO3) = = 0.01547 + 0.00005 mol There are only 0.01547 + 0.00005 mol of NaHCO3 but 0.006331 + 0.00004 mol of CH3COOH is required for the 1.3 g of NaHCO3 to react completely. CH3COOH is the limiting reagent We can also say that the number of moles in 10 cm3 of CH3COOH is 0.006331 + 0.00004 mol, as CH3COOH is the limiting reagent and is the one that is completely used up. ...read more.

Conclusion

Therefore, we only need to find the number of moles of NaHCO3 to find the limiting reagent in group 2. n(NaHCO3) = = 0.005952 + 0.00005 mol Theoretically, 0.006331 + 0.00004 mol NaHCO3 is required to completely react with 0.006331 + 0.00004 mol of CH3COOH There are only 0.005952 + 0.00005 mol of NaHCO3 but 0.006331 + 0.00004 mol of CH3COOH NaHCO3 is the limiting reagent in group 2 Now we know that Group 1 NaHCO3 is the limiting reagent Group 2 NaHCO3 is the limiting reagent Group 3 CH3COOH is the limiting reagent Group 4 CH3COOH is the limiting reagent Group 5 CH3COOH is the limiting reagent Group 6 CH3COOH is the limiting reagent We want to know how much sodium bicarbonate in grams is required to react perfectly with 10 cm3 of diluted CH3COOH which contains 0.006331 mol CH3COOH For it to react ideally, 0.006331 mol of NaHCO3 has to react with 0.006331 mol of CH3COOH NaHCO3) = 0.006331 mol 84 = 0.5318 grams ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our International Baccalaureate Chemistry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Chemistry essays

  1. Rate of Reaction sodium thiosulphate

    The results weren't accurate enough to show a significant graphical representation of a first order reaction and not enough trials were taken to prove that there was a direct relationship because of anomalous results.

  2. Aim: Using an iodine clock reaction to find the order of hydrogen peroxide and ...

    Stop the time when the entire solution has turned black. 8. Repeat with different concentration of the liquids making up solution B. 9. Solutions of different concentrations can be created by increasing the amount of reactant that is being changed by two.

  1. Limiting Reagents. Aim: To investigate the reaction between sodium bicarbonate powder and ethanoic ...

    = = =0.006331 + 0.00004 mol of CH3COOH Theoretically, 0.006331 + 0.00004 mol of CH3COOH would react with 0.006331 + 0.00004 mol of NaHCO3 , because the ratio is 1:1. But, this may not be the case in our experiment, therefore we need to find the number of moles of NaHCO3 n(NaHCO3)

  2. Aim To investigate the chemical properties of alcohol

    + 2H2O (l) --> 2NaOH (aq) + H2 (g) As observed, the metal melts to silver balls due to heat energy that is released by the highly exothermic reaction. The sodium metal shoots to the surface of the water because it has a density less than 1 g/cm3.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work