IB Chemistry Standard

Brionna Wilson

12/11/2009

Determining Faraday’s Constant by Electrolysis

of Copper (II) Sulphate

Aim:

To find the value of the Faraday constant – the electric charge carried by one mole of electrons - from the electrolysis of aqueous copper(II) sulfate solution, using weighed copper electrodes.

Faraday's Law:

The amount of substance consumed or produced at one of the electrodes in an electrolytic cell is directly proportional to the amount of electricity that passes through the cell.

By definition, one coulomb (C) of charge is transferred when a one-ampere (amp) current flows for one second (s):

Introduction:

  1. Excess aqueous 1.0M copper (II) sulphate solution will be electrolysed with copper electrodes.
  2. Oxidation will occur at the anode, and reduction cathode:

Faraday’s Constant can be determined through electrolysis by using the increase in mass of the cathode and the charge in the circuit to calculate the total number of electrons that contributed towards the reduction of the copper ions. One mole of these electrons carries one Faraday of charge.

The following formula can be used to work out Faraday’s constant:

F = Faraday’s Constant

I = current (amps)

t = time (seconds)

M = molar mass of copper (63.55)

n = number of moles of electrons (2; copper ion has a 2+ charge)

w = mass of plated copper (grams)

Variables:

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Requirements:

  • water bath (30oC)
  • 100cm3 1.0M aqueous copper (II) sulphate
  • 2 same-sized copper electrodes (6.90 x 3.00 cm)
  • 3 d.p. balance
  • Burette
  • Voltmeter
  • Ammeter
  • Rheostat
  • thermometer in water trough
  • safety goggles
  • DC power pack
  • connecting leads, including two fitted with crocodile clips, 3
  • Stop clock
  • Balance (3 d.p.)
  • Hot-air blower, such as a hair drier
  • Emery paper
  • Paper towels or tissues

Apparatus:

Technical Notes

  1. It is difficult to avoid fluctuations in current throughout ...

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