• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Case of Doubled screen Maths Investigation

Extracts from this document...

Introduction

This is a portion of the main project taken from between.

Case of Doubled screen(diagram only)

        First max.

        First Max.

GENERALIZATION   FOR   N – SCREENS.

First of all let us consider a simple case in which we find the fringe width on nth screen of first maxima.

The diagram may be

                 S1                S2                S3        S4

N => odd

λ                ……………….

                                                                                                            ……………….

………………..        ………………

………………..        …………………

                           D        D        D        D

Again if n is odd then we would obtain the fringe width d/2 & thus the separation between two maximas

= d.

Therefore, if n is odd then fringe width of first maxima = d /2.

And if n is even, then we would get fringe width greater then that when n is odd and it would be λD/d.

Note: Here we are considering diagram type A, ie n=>odd suppose we considered B, then also we would get same result.

THIS IS A VERY GENERAL CASE IN WHICH WE CAN CALCULATE “ FRINGE WIDTH”

FOR ANY SCREEN NUMBER .THE MAIN PART OF THIS IS THAT WE HAVE

CONSIDERED THIS FOR FIRST MAXIMA.

A MORE GENERAL CASE IS DISSUSED BELOW:

…………………………….

        …………………………….

   d/2         X1    X3    X5       X7     X9          Xn-1

   d/2        X2     X4  X6        X8     X10        Xn

………………………….

        ………………………….

The size of First two slits is “d/2” & distance between the slits is “D’. Now a monochromatic source of light is emitted having wavelength λ .

...read more.

Middle

5+A6)(A9+A10)

Since the fringe width is different for different “As” therefore we

               Break our series in two parts:

                         1\2           TYPE “1”        3\4           TYPE “2”

                        5\6        7\8           have another

typeof fringe width

                       9\10  have a particular         11\12

                    type of fringe width

now the general term of TYPE  “1” series is {4m-3\4m-2} now if we have a no.

(n)such that m=n+3\4  or m=n+2\4 & both “m” & “n” obtained are integers then

we will say that (n) lies in type 1 now each element of type 1 has certain

common factor in it the uncommon factors are1\2=>1

5\6=>(A1+A2)\(A3+A4)

 9\10=>(A1+A2)(A5+A6)\(A3+A4)(A7+A8)

now if we find general term of this series& generalize this situation then we will find general term of type “1” series BY OBSERVATION GENERAL TERM IS

(A1+A2)(A5+A7)(A9+A10)………………………………………………………..[Am+4 + An-4]

(A3+A7)(A7+A8)(A11+A12)…………………..…………………………………..[Am-2 +An-2]

Where m is the maxima no. just prior to n.

NOW FOR TYPE TWO SERIES, the variance is 3\4 =>1\A1+A2

7\8 =>A3+A4\(A1+A2)(A5+A6)

11\12=>(A3+A4)(A7+A8)

(A1+A2)(A5+A6)(A9+A10)

Again by simple observation the general series in this case is:

(A3+A4)(A7+A8)(A11+A12).............................................(Am-4+An-4)

               (A1+A2)(A5+A6)(A9+A10)..............................................(Am-2+An-2)

FINALLY WE OBTAIN:

XN {for type 1}  =ANλ

...read more.

Conclusion

σ  =   λ{D+Y+X1+X2}\X2

        =>X{dtanσ−2λ}   =     λ{D+Y+X1}

>   X2=    λ {D+Y+X1}

        dtanσ−2λ

Consult fig.3           tanσ = λ {D+Y+X1+X2+3X3}

        DX3

        =>X3{dtanσ-3λ}    =  λ{D+Y+X1+X2}

THUS X3 = λ {D+Y+X1+X2}

                dtanσ-nλ

GENERALISITION:

         Xn  =λ{D +Y+X1+X2+X3+X4+….+Xn-1}

                           dtanσ-nλ

We can surely say that f the second max. of screen at an angle will be the  second max. of the arbitrary screen because between first & second max., since their  is no other max. this light rays cant pass in that region & inferred to produce  a maxima. This explanation is also true in case of first-second, second-third and third-forth & ay maxima.

Finally distance of a general max. From central maxima in a screen kept a an angle is:

 An=  λ{D+L\2(cotσ) +X1+X2+X3+……+nXn}

d sinσ

image00.png (A significant result.)

COLOURED FRINGES

If white light of wavelength {400-700} nm is sent through a ydsethen we get colored fringes

 For each of wavelength out of 400-700 we will obtain different fringes & hence different

Fringe width. The first maxima will be formed at different positions as shown below.

The central maxima will be white.

RED

ORANGE

YELLOW

GREEN

BLUE

INDIGO

VOILET

          WHITE LIGHT

 We may obtain some intensity due to λ also. This case may arise a possibility of MAXIMA overlapping between higher order maxima’s.

ANALYSIS ENDS

Shubham Verma

E-mail:-shubahmverma@rediffmail.com

78, new civil lines

Behind Gurudev Palace

Kanpur 208024

UP

...read more.

This student written piece of work is one of many that can be found in our AS and A Level Decision Mathematics section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Decision Mathematics essays

  1. Critical Path Analysis

    After drawing the network, I can show the 'Earliest Arrival Times' which is the earliest time an activity can start due to the duration of previous activities.

  2. Critical Path Analysis: Redecorating a room.

    activities going on within the room, the task will require two workers and will last for 1hr. * D - Assemble wall mirror and frame, These items were purchased and arrived separately to be assembled, assembly will only require one person and will last for 10 minutes * E -

  1. Critical Path Analysis.

    This will have a knock-on effect on the rest of the critical path. The last activity, 'eat and clean away' will be delayed at the same amount of time as the original activity 'cook pasta shells' was delayed. Critical activities can be established when: earliest finishing time (lj)

  2. To Study an Impact on Indias Top B-Schools Performance by Section-wise Placement by ANOVA ...

    We applied ANOVA analysis (two way analysis of variance) to determine the effect of salary package in different sectors offered to students of India?s top b-schools and vice-versa. The average sector-wise placement in 2011 (In LPA) for the three top b-schools (IIM-A, IIM-I, IIIM-K)

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work