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In this experiment, I predict that as the force increases, as will the acceleration. Therefore, as the force decreases the acceleration decreases.

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GCSE Science Coursework : Physics


In this experiment, I predict that as the force increases, as will the acceleration. Therefore, as the force decreases the acceleration decreases. I can also predict that the force and acceleration of an object are directly proportional, meaning that if the force was to be doubled, then the acceleration would also double. I can predict this using Newton’s second law of motion.

Newton’s second Law of motion:

Force      =         Mass x Acceleration

  (N)                    (kg)         m/s

(variable)                      (measurement)

In simple terms, this means that if the force is to increase then the acceleration must also increase because the mass multiplied by the acceleration must equal the force.

The equation, like many others can be re-arranged in order to show a possible prediction for the value in m/s  that the acceleration will be the subject of the equation.

Acceleration     =    Force          (Mass / 0.400kg)


Weight is a force. Weight is quite oftenly confused with mass, however each one differs to the other. Mass is measured in kilograms (kg). The weight of an object only concerns the amount of matter an object is made up of.

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The experiment will be measured on 3 occasions for each variable, these repeat readings will be averaged out into a single figure to gain an accurate set of results.

To prepare for the investigation, a preliminary test was carried out in order to discover which mass of the rider produced the most accurate results.

To do this, the lightest mass of the rider was used with the lightest and heaviest weights (0.020N - lightest) and (0.170N - heaviest).

The masses of the rider were the largest possible (0.400 kg) and the smallest possible ( 0.200kg).

The results showed me that the lighter the mass of the rider, the wider the range of results that I recorded. In contrast, the heavier the mass of the rider was, the more reliable my results were because they provided the smallest range.

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I was able to produce these predictions by re-arranging Newton’s second law to show me what the acceleration of an object can b equal to in terms of its force and mass.

(Old equation)

   Force      =         Mass x Acceleration

    (N)                    (kg)         m/s

(variable)                        (measurement)

(New, Re-arranged equation)

Acceleration     =    Force          (mass / 0.400kg)


I have a range of values for my force,  I inputted each one of these values to gain predicted results.

(When force = 0.02) :    0.02           =        0.05       (Actual average = 0.05)            


(When force = 0.03) :   0.03            =        0.075     (Actual average = 0.07)


(When force = 0.07) :   0.07            =        0.175     (Actual average = 0.08)


(When force = 0.08) :   0.08            =        0.20       (Actual average = 0.20)


(When force = 0.12) :   0.12            =        0.30       (Actual average = 0.31)


As the above figures  display clearly, my results are all highly accurate and sufficiently support my prediction and theory.

All that remains is to discuss how I can extend my investigation. The obvious point that springs to mind is to gather further results to obtain an exceptionally high level of accuracy. However, I can also look to change my variable from the force to the mass of the rider. I can do this by investigating the relationship between the mass and force on a rider to give me additional information.

I can carry out these tests in the same manner as I have discussed for this particular investigation, but changing the variables used. I will use a range of variables that will aid me complete my investigation reaching sufficient conclusions.  

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