To Determine the Enthalpy of combustion of different alcohols.

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Alex Bowles

To Determine the Enthalpy of combustion of different alcohols.

Skill Area P: Planning

Prediction: 

I predict that as the number of carbon atoms in the alcohols increases, the enthalpy (or heat content) increases at a fairly equal rate.

Detailed Scientific Knowledge:

For any reaction to take place bonds must be broken and made, bond breaking requires energy while bond making releases energy. Bonds between different atoms require or release different amounts of energy when broken or made because the bonds are different in strength. The energy that is stored in chemical bonds is called enthalpy and given the symbol H.  By looking at the equation for the reaction and more importantly looking at the bonds that are being broken and made, it is possible to work out an estimate for the amount of energy that will be released in the reaction.  This is called the change in enthalpy.  The enthalpy of a reaction is the change in energy going from reactants to products.  For exothermic reactions, the enthalpy is negative while for endothermic reactions, the enthalpy is positive.  A negative value for the enthalpy, or ΔH denotes that energy has been released into its surroundings, bonds have been made and therefore there is an increase in temperature.  A positive value of ΔH shows that energy has been taken in from its surroundings and bonds have been broken, as there is now more energy and also a decrease in temperature.

The reactions that I am going to be looking at are all combustion reactions and are all exothermic reactions.  This means that energy will be released during the reaction and more bonds will be formed than broken.  It is possible to show a reaction and its ΔH value in terms of a reaction path graph.  Let us take the example of methane reacting with oxygen – a reaction not too dissimilar to the one that I will be carrying out.  By looking at the symbol equation, shown below, it is possible to predict that ΔH will be negative as more bonds are being formed.  

CH4 + 2O2                                                          CO2 + 2H2O

By working out ΔH for this reaction, I will be able to draw a reaction path.  However as I am not doing this experiment, I will use the average bond energies to work out ΔH.  Although this will achieve quite an accurate result, it is not perfect because these are only general bond energies, so the actual bond energies may differ slightly.  To find ΔH, I have to know the following bond energies:

E (C-H) = 412 KJ/mol-1

E (O=O) = 496 KJ/mol-1

E (C=O) = 743 KJ/mol-1

E (O-H) = 463 KJ/mol-1 

For the reactants the bonds being broken are 4 * (C-H), and 2 * (O=O).  Therefore the energy being taken in is 1648 KJ + 992 KJ  = 2640 KJ.

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For the products, the bonds being formed are 2 * (C=O), and 4 * (O-H).  Therefore the energy being given out is 1486 KJ + 1852   =  -3338 KJ.  The energy diagram is therefore shown below:

This method of finding ΔH can be applied to my investigation but I will also compare it to the result of ΔH that I achieved from my experiment.  This can be found using two equations.  For the first one, I need the mass of the water, the temperature rise of the water and the ...

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