222 and all that!

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222 and all that!

Maths Investigation

        

Sayan Dutta Chowdhury     9C

Contents

The Project………………………….Page 3

3 Digit Numbers…………………….Page 4

4 Digit Numbers…………………….Page 6

5 Digit Numbers…………………….Page 9

6 Digit Numbers............................Page 13

The Formula……………………….Page 14

Proving The Formula……………..Page 16

Bases………………………………Page 23

The Project

        Everyone in year 9 was given the “222 and all that!” maths project to do. We had to write down all the three digit numbers that could be made by rearranging the digits 1, 2 and 7. The combinations were 127, 172, 217, 271, 712 and 721. Then by adding those digits, the answer came to 2220. Next we had to add the three digits, i.e. 1 + 2 + 3 = 10. In the end we divided 2220 by 10 giving us 222.

3 Digit Numbers

  1. Make all the combinations using the three   digits.
  2. Add the combinations together.
  3. Add the three numbers together.
  4. Divide ∑ the combinations divided by ∑ the three numbers and the answer will always be 222.

Examples

123 132 213 231 312 321          

Adding the above numbers gives 1332 and 1 + 2 + 3 = 6, so 1332 ÷ 6 = 222.

567 576 657 675 756 765

Adding the above numbers gives 3996 and 5 + 6 + 7 = 18, so 3996 ÷ 18 = 222.  

268 286 628 682 826 862

Adding the above numbers gives 3552 and 2 + 6 + 8 = 16, so 3552 ÷ 16 = 222.

4 Digit Numbers

  1. Make all the combinations using the four   digits.
  2. Add the combinations together.
  3. Add the four numbers together.
  4. Divide ∑ the combinations divided by ∑ the four numbers and the answer will always be 6666.
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Examples

1234 1243 1324 1342 1423 1432 2134 2143 2314 2341 2413 2431 3124 3142 3214 3241 3412 3421 4123 4132 4213 4231 4312 4321

Adding the numbers on the previous page gives 66660 and 1 + 2 + 3 + 4 = 10, so 66660 ÷ 10 = 6666.

2467 2476 2647 2674 2746 2764 4267 4276 4627 4672 4726 4762 6247 6274 6427 6472 6724 6742 7246 7264 7426 7462 7624 7642

Adding the numbers above gives 126654 and 2 + 4 + 6 + 7 = 19, so 126654 ÷ 19 = 6666.

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