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• Level: GCSE
• Subject: Maths
• Word count: 1073

# Emma&amp;#146;s Dilemma

Extracts from this document...

Introduction

Thomas Collyer 10Lr                MATHS

27/04/07                EMMA’S DILEMMA

Page  of

## Aim

To investigate the patterns caused by the permutations of letters in words of different lengths and to investigate the possibility of predicting the number of permutations. To discover a formula that can be applied to all words.

Question 1.

12 different permutations can be made by the name EMMA:

1. EMMA
2. EMAM
3. EAMM
4. MMEA
5. MMAE
6. MEMA
7. MEAM
8. MAEM
9. MAME
10. AMEM
11. AMME
12. AEMM

Question 2.

Middle

ILVECILCEVILCVEIECLVIECVLIELCVIELVCIEVLCIEVCLVECLIVECILVEICLVEILCVELICVELCIVCLIEVCLEIVCIELVCILEVCELIVCEILVICLEVICELVILECVILCEVIECLVIELCVLECIVLEICVLCIEVLCEIVLIECVLICIECILVECIVLECVIEECVEIECLIVECLVIELVICELVCI
1. ELICV
2. ELIVC
3. ELCVI
4. ELCIV
5. EICVL
6. EICLV
7. EILVC
8. EILCV
9. EIVCL
10. EIVLC
11. EVCIL
12. EVCIL
13. EVLIC
14. EVLCI
15. EVILC

120.EVICL

4) Looking at mathematics behind answers

The word Lucy has 4 letters l,u,c and y. If we know how many letters (no repeats) are in a word we can work out the number or permutations by multiplying 1 x 2 x 3 x 4 and so on until we reach the correct number of digits in a word (e.g. a 10 letter word would be 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10). The mathematical symbol for this is n! and stands for number factorial, this shows number of letters! . After working this out we can quickly and easily work out the number of permutations made by a word with repeats – this id done by dividing our previous answer by 2. For 2 repeats we divide the answer again by 2.

Conclusion

! q! ...

(In words: n factorial over p factorial times q factorial and so on)

Example1

How many permutations can be formed from the letters, taken 5 at a time, of the word DADDY?

Solution  (has 3 letters that are the same – D)

5! / 3! = 20

• The 5! Shows the word has five letters in it including repeats.
• The 3! Shows the word has 3 letters that are the same (d)

Example2

Find the number of arrangements of all the letters in the word MARMALADE.

Solution

9! / 2! x 3! = 30240

• The 9! Shows the word has 9 letters altogether including repeats.
• The 2! Shows the word had 2 letters the same (m).
• The 3! Shows the word has 3 more letters that are the same (a).

This formula can be used conclusively for other problems.

In how many ways can 3 apples, 2 oranges, 4 pears and one banana be given to 10 children if each child receives a piece of fruit?

Solution

10! / 3! x 2! x 4! = 12600

This student written piece of work is one of many that can be found in our GCSE Emma's Dilemma section.

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