• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Maths Project : Cubes and Hidden Faces

Extracts from this document...

Introduction

Maths Project : Cubes and Hidden Faces I am finding out if there is a pattern to the ratio of cubes to the number of hidden faces and finding the nth term. With 1 Cube = 1 hidden face With 2 Cubes = 4 hidden faces With 3 Cubes = 7 hidden faces With 4 Cubes = 10 hidden faces With 5 Cubes = 13 hidden faces With 6 Cubes = 16 hidden faces Already I can see a pattern, which is that with each cube, added there are 3 more hidden faces. Now I will try to find the nth term. 1st 2nd 3rd 4th 5th 6th 1 4 7 10 13 16 3 3 3 3 3 3X1=3 and I need 1 3X2=6 ...read more.

Middle

2 cubes = 4 hidden faces. 4 cubes = 12 hidden faces 6 cubes = 20 hidden Faces 8 cubes = 28 hidden faces This time the pattern goes up in 8 and I will now find the nth term. 1st 2nd 3rd 4th 4 12 20 28 8 8 8 8X1= 8 and I need 4 8X2= 16 and I need 12 8X3= 24 and I need 20 8X4= 32 and I need 28 From this I can see that I need to - 4 so the nth term is 8n-4. to find the 100 number of hidden faces times 8 by 100 and -4 which = 796 Now I can draw a table of results with out drawing all the pictures. ...read more.

Conclusion

1st 2nd 3rd 4th 5th 3 10 17 24 31 7 7 7 7 7X1= 7 and I need 3 7X2= 14 and I need 10 7X3= 21 and I need 17 7X4= 28 and I need 24 7X5= 35 and I need 31 I need to - 4 to get the right number so the nth term is 7n-4. To get the number for 100 cubes I will times 7 by 100 and - 4 to get 696. I can now draw a table of results. Number of cubes Number of hidden faces 2 3 4 10 6 17 8 24 10 31 12 38 14 45 16 52 18 59 20 66 22 73 24 80 26 87 28 94 30 101 32 108 34 115 36 122 38 129 Jamie Moore 02/05/07 1 ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our GCSE Hidden Faces and Cubes section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related GCSE Hidden Faces and Cubes essays

  1. An investigation to look at shapes made up of other shapes (starting with triangles, ...

    However, as this proved flawless both for triangles and for squares, I am sure that there is no need - I have checked my workings thoroughly, and I can see no errors. So the formulas linking P, D and H are: P=4H+2-2D D=2H-P/2+1 H=(P+2D-2)/4 'Universal' Formulas After finding 3 successful

  2. Borders Investigation Maths Coursework

    When n = 2 a(2)3+b(2)2+c(2)+d =7 8a + 4b + 2c + d =7 (2) When n = 3 a(3)3+b(3)2+c(3)+d =25 27a + 9b + 3c + d = 25 (3) When n = 4 a(4)3+b(4)2+c(4)+d =63 64a + 16b + 4c + d = 63 (4)

  1. Maths-hidden faces

    l=length, h=height Explanation of final rule: The final rule, h=6(l x w x h) - ((w x l) + 2(h x w) + 2(l x h)), is a more detailed version of the rule h=6n-s. It uses dimensions so that you don't have to count out the number of cubes

  2. An investigation for working out hidden faces as different number of cubes are joined ...

    No of total faces 1 2 3 9 12 2 4 10 14 24 3 6 17 19 36 4 8 24 24 48 5 10 31 29 60 6 12 38 34 72 7 14 45 39 94 From the above table a simple sequences can be formed and

  1. "With reference to theories of visual object recognition outline the ways in which faces ...

    There have been suggestions that faces are recognised differently from objects and this was first indicated through looking at brain-damaged patients who suffer a type of agnosia called prosopagnosia (Gross, 2001). This prevented patients from recognising faces even though their ability to recognise objects remained relatively intact.

  2. Investigate the number of hidden faces when cubes are joined in different ways.

    To check that formula is correct to use to find the number of hidden faces on any cube(s). Let n = 11 (3*11) - 2 = 31 correct. Formula does work! Fundamentally the above working outs show 2 formulas: Formula 1A: Total number of visible faces = 3n + 2

  1. Investigate different sized cubes, made up of single unit rods and justify formulae for ...

    This is because there are 60 rods on one face. 60 multiplied by the 6 faces that are on a cube. 60 x 6 equal 360. There are another 6 faces passing the opposite way with 30 exclusive rods. 30 multiplied by 6 equal 180.

  2. The aim of my investigation is based on the number of hidden faces and ...

    The successfulness of this idea of using the same formula will be reviewed in the conclusion section of my investigation. Second Set Of Cuboids I have decided for my second set of cubes I will line up the cubes in a similar fashion as the first set but with an

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work