The Fencing Problem

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There is a need to make a fence that is 1000m long. The area inside the fence has to have the maximum area. I am investigating which shape would give this.

Rectangles:

I am going to start investigating different shape rectangles, all which have a perimeter of 1000m. Below are 2 rectangles (not to scale) showing how different shapes with the same perimeter can have different areas.

Here are some pure examples of what I have to accomplish with rectangles having perimeters of 1000 metres.

E.g. 1:

E.g. 2:

In a rectangle (of 1000m), any two different length sides will add up to 500m, this is because each side has an opposite with the same length. Therefore in a rectangle of 100m X 400m, there are two sides opposite each other that are 100m long and two sides next to them that are opposite each other that are 400m long. This means that you can work out the area if you only have the length of one side. To work out the area of a rectangle with a base length of 200m, I subtract 200m from 500m, giving me 300m and then times 200m by 300m.

I can then put this into an equation form: 1000 = X (500 -X)

X = Base Length

Below is a table of results, worked out using the formula above. I have gone down the table by taking 10m off the base every time.

There are three columns one showing the height (m) another showing the base length and the final column shows the area (m2).

Base Length

Height (m)

Area (m2)

500

0

0

490

0

4900

480

20

9600

470

30

4100

460

40

8400

450

50

22500

440

60

26400

430

70

30100

420

80

33600

410

90

36900

400

00

40000

390

10

42900

380

20

45600

370

30

48100

360

40

50400

350

50

52500

340

60

54400

330

70

56100

320

80

57600

310

90

58900

300

200

60000

290

210

60900

280

220

61600

270

230

62100

260

240

62400

250

250

62500

240

260

62400

230

270

62100

220

280

61600

210

290

60900

200

300

60000

90

310

58900

80

320

57600

70

330

56100

60

340

54400

50

350

52500

40

360

50400

30

370

48100

20

380

45600

10

390

42900

00

400

40000

90

410

36900

80

420

33600

70

430

30100

60

440

26400

50

450

22500

40

460

8400

30

470

4100

20

480

9600

0

490

4900

0

500

0

I can draw a graph of base length against area using this formula, (Fig 1.0).

According to the table and the graph, the rectangle with a base of 250m has the greatest area. As you can see in the table below I have gone into greater depth to find if the rectangle with a base of 250m is the highest possible area. This shape is also called a square, or a regular quadrilateral. Because I only measured to the nearest 10m, I cannot tell whether the graph is true, and does not go up just to the sides of 250m, so I will have to investigate further by focusing around 250m. I will work out the results using 249m, 249.5 and 249.75, as shown below.

Height (m)

Base (m)

Area (m2)

251

249

62499

250.5

249.5

62499.75

250.25

249.75

62499.9375

250

250

62500

249.75

250.25

62499.9375

249.5

250.5

62499.75

249

251

62499

All of these results fit into the graph line that I have, making my graph reliable, Fig 1.0.
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I have solved that a square has the greatest area of the rectangles group.

Triangles:

My next task is to find the triangle with the largest area. In any scalene or three angled triangle, there is more than one variable so therefore there are "n" combinations. So I'm only going to use isosceles triangles for now. This is due to the fact that if I know the base length, then bearing in mind that the perimeter has to add up to 1000m and I already have the base length I can work out the other two ...

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