The Fencing Problem.

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Phil Bavister

The Fencing Problem

A farmer has exactly 100 metres of fencing and wants to fence off a plot of land.

She is not concerned about the shape of the plot, but it must have a perimeter of 1000 m.

She wishes to fence off the plot of land, which contains the maximum area.

Investigate the shape, or shapes, that could be used to fence in the maximum area using exactly 1000 m of fencing each time.

Firstly I thought about some of the shapes the possible and decided to calculate their areas in a logical order. So I decided to start with triangles before moving onto quadrilaterals, pentagons, hexagons and so on.

Triangles

To calculate the area of a triangle you must times half the base by the vertical height.

Formulae

A = b x h

Equilateral Triangle

There is more than one way to calculate the area of an equilateral triangle so I will demonstrate each of the three different ways.

. A = x x x sin 60

= 48112.52 (to 2d.p.)

2. A = x - 2 x h

h = sin 60 - - 3

= 48112.52 (to 2d.p.)

3. A = ab sin c

= 48112.52 (to 2d.p.)

Isosceles Triangle

A = b x h

To find the vertical height you must split the isosceles triangle into two separate right-angled triangles and use Pythagoras' Theorem. Pythagoras can only be used in right-angled triangles and uses two sides to find the third side.

h = a2 - (b)sq. = Ans.

h =

Formulae

A = b x

Examples

200 x (90000 - 40000 = 50000.

) = 44721.36 (to 2d.p.)

00 x (160000 - 1000 = 150000

) = 38729.83 (to 2d.p.)

Length of Sides (m)

a

b

c

Height (m)

Area (m )

251

498

251

31.62278

7874.071

275

450

275

58.1139

35575.62

300

400

300

223.6068

44721.36

325

350

325

273.8613

47925.72

330

340

330

282.8427

48083.26

333

334

333

288.0972

48112.23

335

330

335

291.5476

48105.35

340

320

340

300

48000

345

310

345

308.2207

47774.21

350

300

350

316.2278

47434.16

375

250

375

353.5534

44194.17

400

200

400

387.2983

38729.83

425

50

425

418.33

31374.75

450

00

450

447.2136

22360.68

475

50

475

474.3416

1858.54

499

2

499

498.999

498.999

This table shows that the isosceles triangle made of integers with the largest area is very similar to an equilateral triangle. This suggests the largest isosceles triangle is in fact an equilateral triangle.
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Right Angled Triangles

If you are given a length you can work out the area by using Pythagoras and Trigonometry.

Length of Sides (m)

a

b

c

Area (m sq.)

50

473.68

476.32

1842.11

00

444.44

455.56

22222.22

50

411.76

438.24

30882.35

200

375.00

425.00

37500.00

250

333.33

416.67

41666.67

300

285.71

414.29

42857.14

350

230.77

419.23

40384.62

400

66.67

433.33
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