An investigation into the effect of changing the concentration of the sodium thiosulphate solution on the rate of reaction between sodium thiosulphate and hydrochloric acid.

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An investigation into the effect of changing the concentration of the sodium thiosulphate solution on the rate of reaction between sodium thiosulphate and hydrochloric acid.

PLAN

  • Introduction

I am going to investigate the effect of concentration on the rate of reaction in an experiment between hydrochloric acid and sodium thiosulphate.

The rate of reaction is a measure of how fast a reaction takes place. The rate of reaction can be found using the equation:

        Rate = measurable change ÷ time taken for that change.

The speed of the reaction can be measured in three ways:

  1. Precipitation – when the product of the reaction is a precipitate which clouds the solution.
  2. Change in mass (usually a gas given off) – a reaction that produces a gas and a difference in mass can be measured.
  3. The volume of gas given off – a gas syringe is used to measure the volume of gas given off.

I am going to measure the rate of reaction in an experiment with sodium thiosulphate solution and hydrochloric acid. I am going to observe the length of time it takes for a cross to disappear when acid is added to sodium thiosulphate. The cross will disappear when a precipitate of sulphur makes the solution cloudy. I am going to change the concentration of the sodium thiosulphate by adding water to it and using a stop clock to see how long it takes for the cross to disappear.

  • The equation for this experiment is:

Na2S2O3 (aq) + 2HCl (aq)                  2NaCl + S (s) + SO2 (g) + H2O (l)

  • The ionic equation is:

S2O3 2- (aq) + 2H+ (aq)                 S (s) + SO2 (g) + H2O (l)

  • Hypothesis

I predict that the higher the concentration of the sodium thiosulphate, the faster the reaction will be, so the cross will disappear in a shorter time. The rate of reaction will increase the higher the concentration of the sodium thiosulphate.

This can be explained using the particle theory. This particle theory states that the particles must collide for them to react. The rate of reaction depends on how often and how hard the reacting particles collide with each other.

The more collisions between the thiosulphate ions and the hydrogen ions in any given time, the faster the reaction will be. So, if the sodium thiosulphate is more concentrated, there will be more particles present so they are more likely to collide, leading to more successful collisions. This speeds up the reaction, increasing the rate of reaction.

I looked in my textbook and I saw that there was an inverse relationship between time and concentration. This means that as the concentration increases, the time decreases.

This is shown on the sketch graph below.

Time

   

   

    Concentration        

I also found in my textbook that rate of reaction and concentration are directly proportional. For example, if the concentration was doubled, say from 0.120 to 0.240, the rate of reaction would also be doubled. This is because there would be twice as many particles to react, so it would take half as much time to react, leading to a rate of reaction which is twice as fast – i.e. doubled.

This is shown on the sketch graph below.

        

Rate of

Reaction

(1 ÷ time)

                Concentration

  • Safety

I am going to perform several experiments, and safety is important when using chemicals. I will take a number of measures to ensure my safety and the safety of those around me.

Firstly, I will wear a lab coat at all times during any experiment. I will also wear goggles when pouring any chemicals and when looking into the conical flask.

I will have my hair tied back so it is not in my way. I will also ensure that my bags and books are placed out of the way so they do not get damaged or in the way of my experiment.

I will also be using a conical flask in the experiment, because it’s shape is such that it will not spit should any violent reactions occur.

I will be performing the experiment in a well-ventilated lab so the sulphur dioxide fumes are not inhaled by anyone.

I will wash the solution away immediately after each experiment with plenty of water, as sulphur stains glassware.

I will make sure that no substances that react violently with sodium thiosulphate or hydrochloric acid are around when I perform the experiment. For example, hydrochloric acid reacts violently with aluminium, magnesium, calcium, sodium and other reactive metals. Therefore I shall make sure that none of these metals are near to where I am carrying out my experiment. Hydrochloric acid can also be corrosive, so I shall be careful when pouring it. The molarity of the acid I will be using is not corrosive, but it is an irritant, so caution is still necessary.  Sodium thiosulphate has fewer hazards, but can be harmful if it is ingested in large quantities.

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  • Fair Test

I will attempt to ensure that the experiments I do will be fair tests. I will do this by naming some things as variables and some things as constants.

Variables

  • I will change the concentration of the sodium thiosulphate, by adding water to it, to observe the results at higher and lower concentration.
  • The volume of the acid may be changed in the preliminary experiments, to find a sensible time for the cross to disappear in the final experiment.

Constants

  • The concentration of the hydrochloric acid will remain ...

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