An investigation into the effect of concentration on the rate of reaction between Sodium thiosulphate and Hydrochloric acid

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Gary Liu U5

An investigation into the effect of concentration on the rate of reaction between Sodium thiosulphate and Hydrochloric acid

When sodium thiosulphate solution reacts with hydrochloric acid, the following reaction takes place:

Sodium thiosulphate + hydrochloric → sodium chloride + sulphur + water + sulphur

         solution                    acid                  solution              dioxide

A kind of yellow precipitate of sulphur will be formed.  We will have to find out how long it takes to cover the whole cross by that mixture after it turns cloudy.  

Planning:

 

Aim:

        

I am going to do an investigation to find out the rate of reaction when using different concentration of sodium thiosulphate mixing with some hydrochloric acid to see the reaction of them.  

Prediction:

        

I predict that as we increase the concentration of sodium thiosulphate solution, it would increase the rate of reaction.  In another words, it would speed up the reaction.  The reaction would take place faster, which means the time it takes to cover the whole cross on a piece of paper would be shorter.  This does that due to the kinetic theory of particles because more particles of sodium thiosulphate are involved, therefore there is a higher percentage of successful collisions between the two chemicals resulting in the cross being obscured from view faster.  

Variables:

I am going to change the concentration of sodium thiosulphate for this investigation, if I don’t keep everything constant, things might go wrong and ruin the whole experiment and therefore spoil my experiment.  

I am going to do each of the experiments at room temperature because it is the best way of trying to maintain a constant temperature.

I am going to keep the concentration of hydrochloric acid the same, also I am going to get the chemical from the same place throughout the experiments, and is also better to get them all at once to ensure that no one has done anything with the chemical, and to make sure that they have the same concentration, because it is possible that they have different concentration with the others even though it says they are both 25 vols.  

The size of the breaker is very important because of the surface area of substance to work out when the cross is obscured from view as thisis what I am using to distinguish when the experiment has finished.  The substances when reacted produce sulphur and that is what obscures the view of the cross and it the depth of the mixture is altered, the experiments will be faulty.

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The cross, which is under the breaker, is very important; this piece of apparatus tells us when the experiment is over as then it is obscured from our view by the sulphur that is produced.

In order to do a fair test, everything has to be the same, even if one of the mixtures is stirred or shake as this gives the particles more kinetic energy which makes them collide faster and therefore have a higher rate of successful collisions.  

In order for the chemical to react, the particles have to collide with each other, ...

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