• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Determination of the relative atomic mass of lithium

Extracts from this document...

Introduction

Determination of the relative atomic mass of lithium To calculate the relative atomic mass of lithium I am going to use two methods. Method 1: I am going to measure the volume of hydrogen produced when a known mass of lithium reacts with H2O Method 2: I will now titrate the solution of lithium hydroxide produced. Method 1 results Mass of lithium (g) Volume of hydrogen produced (cm3) 1: 0.09 173 2: 0.09 176 Treatment of results Assuming that one mole of gas occupies 24000cm3 at room temperature and pressure. 2Li (s) + 2H2O (l) � 2LiOH (aq) H2 (g) I am going to calculate the number of moles of hydrogen, H2 that I had collected: No. ...read more.

Middle

titration is: LiOH + HCl � LiCl +H2O 1 mole of LiOH + 1 mole of HCl give us 1 mole of LiCl + 1 mole of H2O Now I'm going to calculate the no. of moles of HCl used in the titration: No. of moles = ( m(0.100) x v (40) ) � 1000 LiOH = 25 cm3 HCl = 0.100dm-3 = 4.0 � 1000 = 0.004 moles Now I will deduce the number of moles of LiOH used in the titration This is the same number of moles of HCl used in the titration = 0.004 To calculate the number of moles of LiOH, I will have to calculate how many moles present in 100cm3 of the solution from method 1: 100cm3 � 0.004 x 4 = 0.016 moles Now I am going to use the original mass of lithium and this result so calculate the relative atomic mass (RAM) ...read more.

Conclusion

I read wrong because I have checked my calculations so it must have been in either the titration of the amount of hydrogen I collected. Whilst doing the experiment I encountered other problems as well: : The oil that the lithium had soaked up could have affected the mass of the lithium/ 2: The gas inside the measuring cylinder could have been released and therefore giving me the wrong amount and the wrong calculations. 3: during the titration stage I could have been more accurate by having some help to take down the readings while I stop the titration instead of me doing both. 4: The pipette is not 100% accurate in its measurements so that also gave me an in accurate reading. ?? ?? ?? ?? Lee Palser centre no: 10534 Chemistry candidate no: 9110 ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our GCSE Aqueous Chemistry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related GCSE Aqueous Chemistry essays

  1. Marked by a teacher

    Enthalpy of Neutralisation.

    3 star(s)

    c = specific heat capacity of water in JK -1 g -1 (Joules per Kelvin per gramme). ?T = change in temperature in oC = (25 + 24) x 4.2 x (30 - 22) = 49 x 4.2 x 8 = 1646.4 J Moles of Hcl = 25 x 1

  2. The Determination of an Equilibrium Constant.

    17.4 17.05 33.55 7.45 Amount of NaOH(moles) 3.48 * 10-3 3.4 * 10-3 6.7 * 10-3 1.5 * 10-3 Amount of H+ in 250 cm3 mixture(moles) 0.87 0.85 1.675 0.375 Amount of HCl added to mixture(moles) 0.025 0.025 0.025 0.025 Amount of CH3COOH at quilibrium(moles) 0.845 0.825 1.65 0.35 Amount of reacted(produced)

  1. Determine the relative atomic mass of lithium.

    Avoid direct contact with this chemical, wear protected gloves. Lithium hydroxide can cause severe irritation and corrosive damage to eyes. If there is contact with eyes, gently blot or brush away dust quickly. Immediately flush contaminated eye with luke worm and run with water, seek medical attention.

  2. Determination of the relative atomic mass of lithium.

    + 2H2O(l) 2LiOH(aq) + H2(g) If a known mass of lithium is dissolved in water, the volume of hydrogen produced can be used to calculate the relative atomic mass of lithium. This will be the basic thesis for experiment 1.

  1. Determination of the Relative Atomic Mass of Lithium

    I will exclude results that are more or less than 1 standard deviation from the mean in experiment 1 i.e. any results above 9.00 or below 6.58. The new mean of the data excluding the anomalous results is 7.54. This is more accurate than the previous mean.

  2. To find the relative atomic mass of a sample of Lithium.

    and not a cylinder like you would see if it was above or below eye level. This is why there is a continuous line around the glassware. When using a burette so long as the meniscus is measured from the bottom at both the start and end point it will not effect the accuracy unlike in a pipette.

  1. Determination of the relative atomic mass of lithium.

    of my analysis. This is why I had to do part (2), so that I have a figure for the number of moles. Mass of Lithium (g) Initial volume of hydrogen (cm3) Final volume of hydrogen (g) 0.13 0 224 Evaluation (method 1):)

  2. To determine the relative atomic mass of Lithium

    LiOH that I made and I shake it for about ten times for complete mix, I then took a 25cm3 pipette and rinse it with some LiOH and then pipette 25cm3 of LiOH from the same bottle into the clean conical flask.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work