Determine the concentration of limewater.

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To determine the concentration of limewater

The aim of my experiment is to find the concentration of limewater solution in gdm.  To do this, I am required to construct my own experiment and choosing reliable and appropriate apparatus.  I will be provided with 250cm of limewater, which contains approximately 1gdm of calcium hydroxide.  I also have hydrochloric acid, which has a concentration of 2.00-mol dm , which is too concentrated and will need diluting.

Apparatus, equipment and chemicals

Pipette 250cm

Burette

Conical flask 250cm

Volumetric flask 250cm

Graduated pipette

Clamp + stand

White tile

Indicator (methyl orange)

Limewater (250cm with 1gdm of calcium hydroxide)

Hydrochloric acid (2.00-mol dm )

Distilled water

Squeezing pump

Balanced Equation

In order to achieve limewater, dissolved slacked lime in water to get a solution of calcium hydroxide (Ca (OH) 2 )

Quicklime + water --------> slaked lime

CaO (s) + H2O (l) --------> CaCl2 (aq)  + 2H2O (l)   

In this reaction it shows the calcium oxide reacts with water to produce calcium hydroxide.  After adding more water to calcium hydroxide, it produces the saturated aqueous solution known as limewater.

Ca(OH) 2 (aq) + HCl (aq) --------> CaCl2 (aq)  + 2H2O (l) 

Method of procedure

My first task for this experiment is to dilute the hydrochloric acid.  To do this I first needed to work out how many moles I wanted for hydrochloric acid:

Ca(OH) 2 (aq) + HCl (aq) --------> CaCl2 (aq)  + 2H2O (l)  

1gdm of Ca(OH) 2

Morality = no. moles of limewater / volume = 0.013 / 1 = 0.013 mol dm

No. moles of limewater = mass / Mr = 1 / 74.1

Mr of limewater = 40.1 + (16 x 2) + (1 x 2) = 74.1

This now tells me that 25cm of 0.013-mol dm of limewater.  Now I can work out the number of moles.

No. moles of = concentration x volume / 1000 = 0.013 x 25 / 1000 = 3.25 x 10

limewater

Ratio of limewater: Hydrochloric acid = 1: 2

                                                               = 3.25 x 10 : 6.5 x 10

The hydrochloric acid is 2M: 2 moles in 1dm

I need 6.5 x 10 moles of acid.  Now I need to work out the volume of hydrochloric acid like this:

Volume = no. moles x 1000 / concentration = 6.5 x 10 x 1000 / 2 = 0.325cm

I need to aim for a 25cm titre so I want a 25cm titre that contains 6.5 x 10 mol dm

Join now!

Now I need to work out the concentration of hydrochloric acid.

Concentration = no. moles x 1000 / volume = 6.5 x 10 x 1000 / 25 = 0.026 mol dm

I now know that I want 0.026-mol dm of hydrochloric acid for the reaction to work.  But I have been supplied with 2.00-mol solution.  I want 250cm of dilute hydrochloric acid at 0.026-mol dm.  The total no. moles in 250cm is unknown.  250 cm of the solution should be enough to repeat the experiment.  To work out the total no.mole I do this:

No. moles = concentration ...

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