Investigate a factor that influences the rate of decomposition of Hydrogen Peroxide (solution) H2O2 (aq)

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Nana Agyeman. 11V Ms Yates

Investigate a factor that influences the rate of decomposition of Hydrogen Peroxide (solution)  H2O2 (aq)

PLANNING

Hypothesis

The higher the temperature, the faster the rate of decomposition of hydrogen peroxide (H2O2).

        Before I can look at factors that will affect the rate of decomposition of Hydrogen Peroxide (H2O2), I have to consider that on its own hydrogen peroxide’ will not decompose to produce oxygen and water as a result at room temperature.

Hydrogen peroxide         oxygen       +    water

                             2H2O2 (aq)                       O2 (g)               2H2O2 (l)

This equation shows the decomposition of hydrogen peroxide. From doing my experiment I will be testing to see if either oxygen or water was present at the end. This will help me see if I concocted the experiment correctly.

 

In order to speed up the reaction so that it is fast enough for me to be able to measure the rate of decomposition at room temperature in a given time, a catalyst will be added. This catalyst is called Manganese(IV) oxide. This catalyst is a substance which will speed up the decomposition of H2O2. However, the catalyst itself does not take part in the reaction, and is not used up; therefore after the reaction has taken place the same amount of catalyst that was added will remain.  

The catalyst works by providing a convenient surface for the reaction to occur. This then means that the particles collide more frequently with each other and so more collisions results in more bonds breaking which leads to a reaction between particles. The catalyst Manganese(IV) oxide (MnO2) will be used because it will speed up the reaction or decomposition of hydrogen peroxide enough for me to measure the rate by collecting the amount of gas produced.

I can now go on to investigate other factors that will increase the rate of decomposition of hydrogen peroxide with the catalyst manganese(IV) oxide present. These include:

  • Concentration and pressure. This results in more particles being present and so they will collide with each other more frequently. As a result chemical bonds will be broken and a reaction can take place faster.
  • Surface area. This would be mostly used for solids, because increasing the surface area of a solid would mean breaking it into smaller pieces. I would not consider this for this investigation because it would be harder to concoct.

However, the factor I have chosen to look at is temperature and how it affects the rate of reaction. Raising the temperature makes the particles move faster as they are given more energy. This means that more particles will collide with each other per second and so the rate of decomposition or reaction increases. This refers to the collision theory.

The Collision Theory

        A chemical reaction can only occur between particles when they collide with each other. There is a minimum amount of energy which colliding particles need in order to react with each other. If particles have less than this minimum energy then they do not react, as the do not collide strongly enough with each other. This minimum energy is called the activation energy.

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        The faster the particles are going, the more energy they will have. Fast moving particles are more likely to react with each other, because they collide with a stronger force and break bonds easily, and so will react a lot faster. Referring to my factor that I will be investigating, particles will move more quickly if they are heated, which will be achieved by raising the temperature.  

Diagrams to explain my background knowledge.

Before I can go on I have find the ...

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