The aim of this coursework is to investigate one factor that affects the resistance in metallic wires.

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Martin Smith 11Ba2

Key Stage 4 Physics Coursework - Resistance of wires

The aim of this coursework is to investigate one factor that affects the resistance in metallic wires.

Background Information

What Is Resistance?

Resistance is when the metal ions in a wire oppose the flow of electrical current carried by the electrons.

Mathematical Information About Resistance

The Ohm (Ω) is the unit of resistance and is always written as a capital letter. Throughout this coursework that symbol will appear to represent a unit of resistance.

The Mathematical general equation that is used to find resistance is:

R    =    V

            I

R = Resistance (Ω)

V = Voltage or pd

I = Current (Amps)

This is known as Ohms law. The equation means that resistance is proportional to pd and inversely proportional to the current as long as the temperature is constant. The reason why temperature is important is because the slightest increase in temperature could cause the atoms in a wire to vibrate more which would change the resistance of the wire. This idea will be explored further in future sections of this coursework

You can use this formula to find the resistance of an electrical component. You need to know the current by measuring the number of amps across the component using an ammeter. You also need to know the voltage or pd across the component and you would measure that using a voltmeter. You then substitute these numbers into the equation to calculate the resistance.

What Causes Resistance In Wires?

Resistance is caused by the electrons that carry the electrical charge colliding with the metallic ions within the wire. Electrons are accelerated from the ‘–’ (negative) end of the wire to the ‘+’ (positive) end of the supply, and when the electrons move along this path, they collide with the metallic ions.

The amount of collisions that an electron makes means more resistance. Therefore twice the number of collisions means twice the resistance.


What Factors Affect Resistance?

There are many factors that affect resistance, but here are four of the factors that affect resistance:

  • Thickness/Diameter/Cross-sectional area






    Thickness, diameter and cross-sectional area affect the resistance because of the amount of gaps that will be available within the wire for the electrons to move through. The more gaps means there are more paths for an electron to take, so therefore there will be less resistance, however, when there are fewer gaps available, there are fewer paths for the electrons to move through, so therefore there is higher resistance. The diagrams below illustrate this idea.



















  • Materials
    All materials are structured differently, and have different density’s (the number of molecules per cubic centimetre), and also have different ways of arranging the molecules within the material, and this will affect the paths that the electrons can take, which has an impact on the resistance. That is how materials affect resistance
  • Temperature
    When it gets hot, molecules vibrate more and are further away from each other. When it is cold, molecules vibrate less and are closer together. In a wire, this means that when the metal ions are hot and are vibrating, it’s harder for the electrons to get through and therefore the resistance is higher.



  • Length
    When a wire is longer, this means that there are more collisions and so there is higher resistance. So for instance, when there is twice the length of a wire, then there is twice the resistance of the original length. Also, putting wires together that have different resistances, e.g., putting a 5Ω resistance wire together with a 10Ω resistance wire means you are putting those two resistances together and then they are added together to give a total resistance of 15Ω.
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What Factors Could You Investigate?

I shall now discuss the viability of investigating these factors. I only have to choose one factor to investigate however.

  • Thickness/Diameter/Cross-sectional area
    This is a factor that is possible to investigate, because it will give me a line graph to allow me to predict for future experiments and therefore I can prove a prediction if I investigated this factor, however, there is an awful lot of complex maths involved which would be time-consuming to have to do for every single possible area, and would not be as viable as other factors to ...

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