• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

Experiment to Measure the Heat of Fusion of Ice

Extracts from this document...

Introduction

Diana Herwono D 0861 006

Title:         Experiment to Measure the Heat of Fusion of Ice

Aim:

The aim of the experiment is to measure the heat of fusion of ice. This is the amount of heat energy needed to change one gram of ice at its melting point (0°C) into one gram of water at the same temperature.

Apparatus:

Calorimeter, balance, set of metric basses, thermometer, warm water, ice, paper towels

Introduction:

When a substance changes state, it absorbs or releases a large quantity of heat. During the change of state, the temperature remains constant. The quantity of heat required to change a

Middle

1. Then immediately add several cubes of ice that have been dried with paper towels.
1. Continue stirring slowly until all ice has melted and the mixture reaches a steady temperature. Record the temperature of the ice-water mixture (T2).

5.        Obtain the mass of the calorimeter and the mixture (mc + w + i).

6.       Use these data to calculate the heat of fusion of ice.

Data Collection:

 Trial 1 Trial 2 Mass of Calorimeter mc (g) 183.5 183.5 Specific Heat of Calorimeter cc (J/g°C) 0.9 0.9 Mass of Calorimeter and Warm Water mc + w (g) 290.5 302 Mass of Warm Water mw (g)mw = mc + w – mc 107 118.5 Specific Heat of Water cw (J/g°C) 4.19 4.19

Conclusion

= (20181 – 33.4*4.19*43) / 33.4 = 424 J/g

Average Value Hf = (454 + 424) / 2 = 439 J/g

Error Analysis:

The accepted value for the heat of fusion of ice is 334 J/g.

Percent Error = (439 - 334) x 100 / 334

=  31.4 %

Sources of error: Some heat is lost to the environment because the calorimeter is not a perfect insulator.

Conclusion:

According to this experiment, the heat of fusion of ice is 439 J/g. However, the accepted value for the heat of fusion of ice is 334 J/g. There is obviously some error in this experiment.

Future Improvements:

To limit the heat lost to the environment, better apparatus should be used (i.e. better insulating materials for the calorimeter). Using larger quantities of ice and water and conducting the experiment repeatedly would eventually cause errors to have a smaller effect on the result, such that the result of the experiment approaches the accepted value.

This student written piece of work is one of many that can be found in our International Baccalaureate Physics section.

Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

Related International Baccalaureate Physics essays

1. Heat of fusion of ICE

Hf = heat of fusion of ice (J/g) cw = specific heat of water (J/g?C) ?Ti = T2 = difference in temperature between that of the ice and the final temperature of the mixture (?C) ?Qlost = ?Qgained By substituting values of mc, cc, mw, cw, mi, ?T, and ?Ti,, we can solve for Hf.

2. Specific latent heat of fusion of ice

- (mass of calorimeter)). * Then I measured and recorded the temperature of ice as T2. * Then after adding the ice to the calorimeter, immediately I added the hot water to the calorimeter and straight away covered the calorimeter in order to avoid any heat loss to the atmosphere.

1. IB Latent Heat of Fusion of Ice Lab

+ (0.10 � 13.00 � 100) %)) + (180.88 J � ((0.01 � 36.14 � 100) + (0.10 � 13.00 � 100)

2. IB Specific Heat Capacity Lab

= � 0.02 g = (0.02 � 64.35) � 100 = 0.031 % Temperature change of water + Calorimeter (?T) (7) - (5) (see data table) (T2 - T1) = 26.00 - 22.00 = 4.00 oC � (0.25 + 0.25)

1. specific heat of a solid

current (�0.01?) time (�0.01s) E (�0.03J) 12 4 0 0 12 4 30 1440 12 4 60 2880 12 4 90 4320 12 4 120 5760 12 4 150 7200 12 4 180 8640 12 4 210 10080 12 4 240 11520 12 4 270 12960 12 4 300 14400

2. LATENT HEAT OF FUSION OF ICE

measure the initial temperature of water, and record data. 5. Measure the container with water, then calculate the mass of water. 6. Put the ice into the water. 7. After the disappear of the ice, measure the mass of the caontainer and calculate the mass of ice.

1. Finding the latent heat of fusion

I repeated this process until the end by subtracting the following value by the preceding. (? g) Run 2: to calculate the change in mass of trial 1 I used the second entry and subtracted by first entry. I repeated this process until the end by subtracting the following value by th preceding (?

2. HL Physics Revision Notes

reaction have greater binding energy per nucleon when compared with the reactants. Topic 8: Energy, power and climate change: Thermal energy may be completely converted to work in a single process, but that continuous conversion of this energy into work requires a cyclical process and the transfer of some energy from the system. • Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to
improve your own work 