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# Investigate the relationship between voltage and Current.

Extracts from this document...

Introduction

Science Coursework on Current and Voltage. Aim: To investigate the relationship between voltage and Current. Equipment List * 1* Power Pack (2-12v) * 1* Resistor (3.9 ?) * 1* Resistor (10.5 ?) * 1* Ammeter * 1* Volt meter * 20* Wires Method We are going to investigate the relationship between Current and Voltage. First we take a power pack and connect 1 wire from the power pack to a 3.9-ohm resistor. Then connect a wire from the other side of the resistor to an ammeter. Then connect the other side of the ammeter to the other side of the power pack. Then connect another 2 wires from each side of the resister to each side of a voltmeter. Switch the knob on the Power pack to 2 volts and turn on the ammeter, voltmeter and finally the Power pack at the mains. Record the reading of the meters on a chart. Like this: ??? Resistor VbR A V Key 2 VbR = Voltage before Resistance 4 A= Amps 6 V= Volts 8 10 TIP: If the ammeter or voltmeter is reading negative numbers switch the wires round on them. ...read more.

Middle

Prediction I predict that the current will be slightly larger in the circuit with the lamp because the lamp will have less resistance than the resistor as the resistor is designed to resist the current. The current will obviously increase as the voltage increases in both of the circuits. From preliminary work I know that Voltage (V) equals (=) Current (I) times (*) by Resistance(R). This is Ohms law and can be put in a triangle like this. V I R (V=I*R) Results 1 Attempt 1 3.9? resistor VbR A V Key 2 0.22 0.84 VbR = Voltage before Resistance 4 0.63 2.43 A= Amps 6 0.99 3.62 V= Volts 8 1.43 5.55 10 1.86 7.20 Attempt 2 3.9? resistor VbR A V 2 0.23 0.85 4 0.63 2.45 6 0.98 3.62 8 1.43 5.53 10 1.86 7.20 Attempt 3 3.9? resistor VbR A V 2 0.23 0.86 4 0.63 2.45 6 0.98 3.62 8 1.43 5.52 10 1.85 7.19 Average 3.9? resistor VbR A V 2 0.23 0.85 4 0.63 2.44 6 0.98 3.62 8 1.43 5.53 10 1.86 7.19 Results 2 Attempt 1 10.5? ...read more.

Conclusion

Voltage and Current are both dependant on resistance so if the resistance was different we would have inaccurate results. (V=I*R). I would also keep the resistor the same one for all 3 experiments in its category. The same 3.9-ohm resistor 3 times and the same 10.5-ohm resistor 3 times Conclusion Looking at my results I can see a fairly clear pattern. It looks like some of the numbers in the A column of the average results are related to the V column next to it. In the A column there is a decimal e.g. 0.25. In most of the results, it has been multiplied by 10 and either rounded off or another number put on the end. Evaluation I think that my experiment went fairly well and my results were fairly accurate. I could have cooled the lamp down in between experiments to make it more of a fair test. I thought my method was good even though it took some preliminary work to help me out. I didn't have any major anomalous results and I think that if I do this experiment I will calculate the relationship between resistance and temperature by measuring the temperature of the lamp. ...read more.

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