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GCSE: T-Total

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  1. GCSE Maths questions

    • Develop your confidence and skills in GCSE Maths using our free interactive questions with teacher feedback to guide you at every stage.
    • Level: GCSE
    • Questions: 75
  2. Marked by a teacher

    T-total coursework

    5 star(s)

    is (n-19) as it has been decreased by 1. The cell to the right of (n-18) is (n-17) as it is 1 more than (n-18). When these 5 terms are added together I get: (n) + (n-9) + (n-17) + (n-18) + (n-19) = 5n - 63 The calculation above shows that the sum of the 5 terms within the T-shape is 5n - 63, therefore I can make a proper formula: T = 5n - 63 where T is the T-total and n is the T-number T-number (n) T-total (T) T-total using formula (5n-63) 20 37 (5x20)= 100 100-63 = 37 26 67 (5x26)= 130 130-63 = 67 50 187 (5x50)= 250 250-63 = 187 80 337

    • Length: 2995 words
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    T-TOTALS

    4 star(s)

    * When the T-Number is even, the T-Total is even. I will now find a rule which links the T-number with the T-Total: n+(n-8)+(n-16)+ (n-18)+(n-17) =5n-56 When n=36 =(5x36)-56=124 Testing: 19+20+21+28+36=124 As you can see my rule has worked. T-Totals - Any sized Grid I will now find the general rule for any sized grid, which links the T-Number with the T-Total. n+(n-G)+(n-2G) +(n-2G-1)+(n-2G+1) = 5n-7G When n=65, and G=10 =(5x65)-(7x10)= 255 44+45+46+55+65= 225 As you can see my rule has worked. Translation: If I translate the T 3 Vectors right, it will become: 22+23+24+33+43= 145 25+26+27+36+46= 160 T-Number=43 T-Number=46 T-Total= 145 T-Total=160 * The T-Total has increased by 15.

    • Length: 1156 words
  4. T-totals. I am going to investigate the relationship between the t-total, T, and the t-number, n. The t-number is always the number at the bottom of the t-shape when it is orientated upright.

    The t-total, T, can therefore be written in terms of the t-number, n, as T= 5n - 63. Using similar reasoning we can express T in terms of n in an 8×8 and 10×10 grid. T-shapes in an 8×8 grid 1 2 3 4 5 6 9 10 11 12 13 14 17 18 19 20 21 22 25 26 27 28 29 30 33 34 35 36 37 38 41 42 43 44 45 46 n T T=5n-56 18 34 5(18)-56=37 21 49 5(21)-56=52 42 154 5(42)-56=67 45 169 5(45)-56=172 The t-total increases by 120 when the t-number is increased by 24 and by 15 when the t-number increases by 3.

    • Length: 4165 words
  5. Objectives Investigate the relationship between the t-totals and t-numbers. To translate the t-shape to different parts of the grid.

    (x*5), where x is the number of times you are moving to the right, so if I translate to the right once it would be new T-total = current T-total + (1x5), T-total = T-total + 5, if I translate 5 times to the right it would be new T-total = current T-total + (5*5), T-total +25. Proof At T-18, if I translated twice to the right, Formula: 'Current T-total + (x*5)' x is the number of times you translate to a certain direction, in this case the right.

    • Length: 7061 words
  6. Relationship between T-total and T-number I am going to investigate T-totals and T-numbers on a 9x9 grid.

    So far I have noticed that when the T number increases by one, the T total increases by 5. I predict that if I move the T shape across once more I will get a T total of 52. I am going to do 2 more T shapes to confirm my prediction. T total = 4 + 5 + 6 + 14 + 23 = 52 T number = 23 T total = 5 + 6 + 7 + 15 + 24 = 57 T number = 24 I have tested my prediction and have found that my prediction was right.

    • Length: 986 words
  7. T-Shapes Coursework

    2 6 10 16 3 9 11 20 4 12 12 24 5 15 13 28 6 18 14 32 4) Data Analysis From the table, it is possible to see a couple of useful patterns: 1) The Sum of the Wing is always 3 times the Middle Number; 2) The Sum of the Tail is always 8 more than the Middle Number; 5) Generalisation It can be assumed that for all possible locations of the 3x1 "T" on the width 8 grid, these patterns will be true.

    • Length: 7605 words
  8. Mathematics Coursework - T Shapes

    17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 Here is a table showing the results so far for the different grid sizes, t-numbers, t-totals and the vector.

    • Length: 704 words
  9. T shapes. I then looked at more of these T-Shapes from the grid in sequence and then by tabulating these results I could then work out a formula.

    T- Number times 5 T-Total 100 37 105 42 110 47 115 52 120 57 125 62 From these results I can now predict that relationship formula is that 5 times the T-Number - 63. To help prove that this is true I will now rather than calling it the T-Number I will call it 'n'. This then means that: Formula= 5n - 63 n-19 n-20 n-21 n-9 n If now use the Formula in the T-shape and use 'n' it is now shown that there are 5 'n' in the T-shape.

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  10. Investigate the relationship between the T-total and the T-number in the 9 by 9 grid.

    In this way we have a T-shape where the bottom (T) number is 'n' and from this we can work out the others. The number above 'n' will be 9 less that 'n' itself because of the size of this particular grid in which there are nine numbers in each row. The number above that one will be 'n-18', because it will again be 9 less than the last number as the properties of the number square dictate. The two either side of this will have to be 'n-19' and 'n-17', because of the fact that the number square goes up in units of one.

    • Length: 1853 words
  11. T Total and T Number Coursework

    N=25 30 35 5 5 The formula for this is Tn5-35 These are the formulas to work out the t-totals on the grid sizes that they are written next to. The Different Formula for each Grid After investigating on the five different grid sizes I have found five different formulas. I shall use these different formulas to find a general formula for the T-total of any grid size. So far the formulas that I have found are; 9x9 Grid; T=5n-63 8x8 Grid; T=5n-56 7x7 Grid; T=5n-49 6x6 Grid; T=5n-42 5x5 Grid: T=5n-35 Now that I have found the individual formulas I shall check that they are correct using a different T- number of the particular grid in question.

    • Length: 3897 words
  12. In this section there is an investigation between the t-total and the t-number.

    19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 We all ready know the answer to the one in red. To work out the one in green all we have to do is work out the difference in the t-number and in this case it is 54.

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  13. For my investigation, I will be investigating if there is a relationship between t-total and t-number. I will first try to find a relationship between T-number and T-Total on a 9x9 grid then change the variables such as grid size.

    56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 First I put the T shape onto my 9x9 grid and translated it right by 1 space each time. As shown above I started on 20 and finished on 25 I then constructed the tale below. T-Number (T) T-Total (N) Difference 20 1+2+3+11+20=37 - 21 2+3+4+12+21=42 5 22 3+4+5+13+22=47 5 23 4+5+6+14+23=52 5 24 5+6+7+15+24=57 5 25 6+7+8+16+25=62 5 The table above shows the difference between the consecutive T-Totals as the T-Number increases by one.

    • Length: 2692 words
  14. For my investigation, I will be investigating if there is a relationship between t-total and t-number. I will first try to find a relationship between T-number and T-Total on a 9x9 grid

    56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 First I put the T shape onto my 9x9 grid and translated it right by 1 space each time. As shown above I started on 20 and finished on 25 I then constructed the tale below. T-Number (T) T-Total (N) Difference 20 1+2+3+11+20=37 - 21 2+3+4+12+21=42 5 22 3+4+5+13+22=47 5 23 4+5+6+14+23=52 5 24 5+6+7+15+24=57 5 25 6+7+8+16+25=62 5 The table above shows the difference between the consecutive T-Totals as the T-Number increases by one.

    • Length: 2692 words
  15. T-shapes. In this project we have found out many ways in which to solve the problem we have with the t-shape being in various different positions with different sizes of grids.

    19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 We all ready know the answer to the one in red. To work out the one in green all we have to do is work out the difference in the t-number and in this case it is 54.

    • Length: 4144 words
  16. Translate the T-shape to different positions on the grid Investigate the relationship between the T-total and the T-number

    is 12. * The difference between the differences along the bottom row ( 4, 5, 6 ) is also 12. T = (n - 19) + (n - 18) + (n - 17) + (n - 9) + n = 5n - 63 T- total = 5n - 63 T = (n - 19) + (n - 18) + (n - 17) + (n - 9) + n = 5n - 63 T- total = 5n - 63 I can use these equations to find the t-totals just from knowing the T-number. I predict that if the T-number is 50 then (5x50)

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  17. T-Total. I will take steps to find formulae for changing the position of the T in many ways using methods such as translation and rotation.

    then I will work on 180 degrees * Rotation will be my final part of my investigation * All the way through my work I will be including explanations and diagrams * As well as using explanations of what I am doing, I will explain why I am doing it and why I get the answers I do * I will be stating all the variables and when I add a new variable I will clearly state what it is.

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  18. The investiagtion betwwen the relationship of the T-number and T-total

    55 5 26 60 5 27 65 5 28 70 5 From these results I worked out that the Nth term was 5Tn - 70. However this only applied a 10 by 10 grid and so if I wanted a formula that applied to any grid then I would have to make all the parts to my formula dependant upon the grid size. For this I needed some new lettering. I needed letters that were dependant on the grid size so I used M to represent the increase in value in one movement down the grid, and R to represent the increase in value in one movement right in the grid.

    • Length: 1988 words
  19. T-Shapes Coursework

    This is an example T-Shape that I will be using to show you how to find the T-Total and T-Number, which I took from the above 9x9 grid. 1 2 3 11 20 T-Total: Found, by adding up all the numbers within the T-shape. The sum of these numbers equals the T-total. Therefore, for example the T-shape above, the T-total would be 1 + 2 + 3 + 11 + 20, so therefore the T-total is 37. T-Number: The number 20, which is at the bottom of the above, is referred to as the T-number, or Tn.

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  20. T totals. In this investigation I aim to find out relationships between grid sizes and T shapes within the relative grids, and state and explain all generalizations I can find

    61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 From these Extra T Shapes we can plot a table of results. T-Number (x) T-Total (t) 20 37 26 67 49 182 50 187 52 197 80 337 From this table the first major generalization can be made, The larger the T-Number the larger the T-Total The table proves this, as the T-Numbers are arranged in order (smallest first)

    • Length: 8274 words
  21. T-total Investigation

    The first part of my formula is therefore 5T. It is 5T because that is how many numbers inside the T. I multiplied the difference between the T-total which is 5 by the T-no. Underneath is my working out: 22 x 5 =110 23 x 5=115 24 x 5=120 I then took away the T-total numbers so that I could find the difference between the T-no and the numbers in each of the 4 squares inside the T. 110- 40 =70 115- 45 =70 120- 50 = 70 I found out that the difference is 70.

    • Length: 4292 words
  22. T totals - translations and rotations

    The number directly above this is 1 place back in the grid so it is N-1-1= N-2. The two remaining numbers in the T shape are N-2+9 and N-2-9. Thus the T total is: N+ (N-1) + (N-2) + (N-2+9) + (N-2-9) = 5N-63 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56

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  23. T-totals, Main objective of this project of T-totals coursework is to find an inter-relationship between the T-total and the T-number.

    may be too small for the process of either horizontal or vertical movement of a particular t-shape to be restricted. This booklet describes methods and calculations used in effort to complete the main objectives of the GCSE Mathematics Coursework 2007-2008 (T-totals). Contents: Introduction. T-total, T-number.............................................................3 Methods.........................................................................................5 Evaluation of Results.........................................................................8 Introduction. T-total, T-number. This coursework is about trying to find a connection between the t-totals and t-number according to the t-shape Here is an example of a T-shape drawn on a 9 x 9 number grid 1 2 3 4 5 6 7 8 9 10 11 12 13 14

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  24. In this investigation Im going to find out relationships between the grid sizes and T shapes within the relative grids, and state an explanation to generalize the finding using the T-Number

    of 30, and the T-total (t) adds up to 87 (11+12+13+21+30). With the second T shape with a T number of 31, the T-total adds up to 92, by looking at the two results a trend can be seen therefore suggesting the larger the T number the larger the total. By looking at the T-Shapes we can plot a table of results. T-Number (n) T-Total (t) 30 87 31 92 32 97 33 102 34 107 By looking at my table of results a pattern can be seen between the T-Number and the T-Total, there's also a relationship between the T-Number and the T-Total because a trend occurs as you move it over different parts of the grid and it gives a ratio of 1:5.

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  25. T-Totals (A*) Firstly I have chosen to look at the 9 by 9 grid. I will be taking five t-numbers in a row and investigating the t-totals for them. Once I have completed all five, I will then look for a formula to link those five

    The t-total is 32+23+15+13+14 which will give us 97. T-number: 32 T-total: 97 Number 4: 14 15 16 24 33 The t-number in this case will be 33. The t-total is 33+24+14+15+16 which will give us 102. T-number: 33 T-total: 102 Number 5: 15 16 17 25 34 The t-number in this case will be 34. The t-total is 34+25+15+16+17 which will give us 107. T-number: 34 T-total: 107 Formula: After investigating the t-numbers from 30 to 34 and comparing them with their t-totals, I have noticed that every time I increase the t-number by one the t-total goes up by five.

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  26. I am going to investigate the relationship between the T-Totals and T-numbers when the T-shape is translated in different sizes of grids

    it shows us 37 and when skipping one place you get 47 the same thing is done to 42 and skipping a place will give you 52. Which will give me the following pattern: T + 5 N + 1 ratio 1:5 Now we got this information so we can find the formula. I have found a formula which is 5N - 63 = T I have worked this formula by T-Number subtracting The T total which would look like this: (N-11)

    • Length: 1297 words

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