• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# I am going to use some physics principals to find out the height of the shot; the range of the shot and the initial velocity of the ball

Extracts from this document...

Introduction

Planning Introduction The experiment was that two video cameras filmed a tennis launcher firing a tennis ball into the sky. One camera was set up near the launcher to get the 7 slides of the ball's motion. Each slide is separated by 0.04 seconds. It was pointing at right angles to the path of the ball. The experiment was repeated with another camera set up far away the launcher to get 25 slides of the ball's motion. Each slide is separated by 0.08 seconds. Aim: I am going to use some physics principals to find out the height of the shot; the range of the shot and the initial velocity of the ball. I will plot the graphs to find patterns of the data then associate the graphs to find out some information. Also I will compare the value of near shot with the value of far shot. Theory: Formulae: a = (v - u) / t t = (v - u) / a v = u + at v2 = u2 + 2as s = ut + 1/2 at2 "s"--Displacement ( metre) "t"--Time ( second) "u"--Initial Velocity ( metre/second) "v"--Final Velocity ( metre/second) "a"--Acceleration ( metre/second2) Prediction These two graphs are drown roughly. ...read more.

Middle

Range Secondly I want to calculate the range of the near shot. Form the graph you can see the distance in an interval time does not change too much, because the vertical acceleration of the ball is 0 if ignore the air resistance. Without the acceleration the velocity will not change at all. In the real life you can't ignore the air resistance so the rate of increasing the distance is slight changed. First I should work out the initial velocity horizontally. Basically the method is the same as calculating the initial vertical velocity. "u" - initial horizontal velocity "D1" - distance of the first point "D2" - distance of the second point "t1" - time of the first point. "t2" - time of the second point u = (D2 - D1)/ (t2-t1) = (0.54 - 0.00)/ (0.04-0.00) = 13.50m/s The time for the ball to reach the highest point is the same as to move the half range so if I can work out how long it takes to reach the highest point then I can calculate the range. Vertical: a = (v-u)/t t = (v - u)/a = (0 - 9.50) / (-9.80) = 0.97s Horizontal: s = ut = 13.50 � 0.95 = 13.10cm = 13.10m So the whole range = 13.10 � 2 = 26.20 m Here you should separate the calculation into two parts vertical and horizontal. ...read more.

Conclusion

The uncertainty of taking the value of the time is+/-0.002s There are some errors on the basic data. I have labeled on the graph. Data Near Shot Displacement/cm Photo Scaled up Photo Time/s x y x y 1 0.00 0.00 0.00 0.00 0.00 2 0.04 2.70 1.90 54.0 38.0 3 0.08 5.50 3.50 110 70.0 4 0.12 8.00 5.00 160 100 5 0.16 10.80 6.90 216 138 6 0.20 12.50 7.50 250 150 7 0.24 15.10 8.90 302 178 Far Shot Displacement/cm Photo Scaled up Photo Time/s x y x y 1 0.00 0.20 0.10 22.8 11.4 3 0.08 1.50 0.90 171 103 5 0.16 2.70 1.80 308 205 7 0.24 4.00 2.50 456 285 9 0.32 7.20 3.00 821 342 11 0.40 6.40 3.50 730 399 13 0.48 7.50 3.90 855 445 15 0.56 8.50 4.30 969 490 17 0.64 9.60 4.50 1094 513 19 0.72 10.6 4.60 1208 524 21 0.80 11.6 4.50 1322 513 23 0.88 12.7 4.40 1448 502 25 0.96 13.7 4.20 1562 479 27 1.04 14.7 3.90 1676 445 29 1.12 15.8 3.60 1801 410 31 1.20 16.6 3.20 1892 557 33 1.28 17.5 2.90 1995 331 35 1.36 18.5 2.40 2109 274 37 1.44 19.3 1.70 2200 194 39 1.52 20.1 0.90 2291 103 41 1.60 21.0 0.40 2394 45.6 43 1.68 21.7 -0.70 2474 -79.8 45 1.76 22.6 -1.30 2576 -148 ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our GCSE Forces and Motion section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related GCSE Forces and Motion essays

1. ## Investigating factors that affect the bounce height of a squash ball

5 star(s)

I therefore decided to employ the assistance of a ball-release mechanism to allow me to release the ball with my eye lower down, so I could get a better idea of how high the bounce was. Even after changing this, I found that it was fairly difficult to accurately measure how high the squash ball bounced.

2. ## Bouncing Ball Experiment

restitution = 0.7 30% of the energy that the ball hits the floor wit is lost. 70% is retained. If the coefficient to restitution = 0.7, a ball dropping from h1 in a vacuum would reach the height of 0.7 h1 after bouncing.

1. ## Squash Ball and Temperature Investigation

For this reason, to make the test fair, the same sized ball with the same diameter will be used. * Type of Surface Different surfaces have different smoothness and changing the surface half way during the experiment will make the test unfair as some surfaces according to their smoothness will

2. ## How does the temperature of a squash ball affects the impact time of the ...

10-3s Uncertainty = 6. Temperature = 70.0+0.4 oC Trial 1 2 3 4 5 6 7 8 9 10 Mean Rebound height/cm 60.4 60.6 60.6 61.6 61.8 61.8 62.6 62.6 62.8 63.2 61.8 Impact time/0.001s 16 19 19 20 20 20 21 21 22 24 20.2 Uncertainty of height=0.1cm Uncertainty of time=0.001s Mean height

1. ## In this experiment I aim to find out how the force and mass affect ...

The light gate may not have been one hundred percent perpendicular to the picket fence causing a small in accuracy in the results. This is shown in Diagram 4. The wheels on the trolley may have caused some runs to be slow and some to run normally which would severely affect the acceleration when calculated in the results.

2. ## This investigation is associated with the bounce of a squash ball. I will be ...

Some materials (like sprung steel) store a lot of energy and are described as having high resilience; others (like putty) store very little and therefore have low resilience. Squash balls, being made of a rubber compound, are of fairly low resilience. Unfortunately, the lower the resilience of an object, the higher the proportion of the energy used in deforming it must be dissipated.

1. ## Investigation into the range of a ski jump

An odd result is spotted (circled). Further points can then be recorded around the odd result. A new trend can now be noticed. Without plotting the extra points, the result would just have been taken as an anomaly. Therefore drawing a graph alongside the experiment place allows for greater scientific accuracy and better end results.

2. ## Investigating the amazingness of theBouncing Ball!

Having said that, when dropping the ball I may still unintentially throw the ball down which could be the effect of any movement made by hand other than dropping the ball. So I would simply place the ball on top of the metre ruler and due to the lack of

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to