• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month
  1. 1
  2. 2
  3. 3
  4. 4
  5. 5
  6. 6
  7. 7
  8. 8
  9. 9
  10. 10
  11. 11
  12. 12
  13. 13
  14. 14
  15. 15

trigonometric functions

Extracts from this document...



Type 1 investigation

Transformation of Trigonometric Functions

Investigate the function:

        y = a sin b(x-c) + d   in respect to the transformation of the base curve of y = sin x, depending on the values of a, b, c, and d. Be sure to consider all possible values for a, b, c, and d.

Describe the base curve

Start with a (try some values)

Then try values in b (sin2x, sin -3x, sin1/2x)

Does your hypothesis hold true for y = cos(x) and y = a cos b (x-c) +d? How about tan(x)?

Transformation of Trigonometric Functions


The purpose of this study is to examine the transformation of trigonometric functions of y=A sin B (x-C) + D and determine the effect on the base curve y=sin(x). I am going to be systematically changing the values of A, B, C and D in the equation y= A sin B (x-C) +D. First I am going to examine different numbers for the value of A. I am going to use whole numbers, negative whole numbers, positive rational numbers and negative rational numbers for the value of A and see how this affects the Sine curve. Then I will examine different numbers for B, then C then D.

...read more.


              Figure 9                                                Figure 10

These graphs show that my prediction was correct, as figure 9 shows that the minimum value is -0.4 and figure 10 shows that the maximum value is 0.4, and both figures show that the period is 2 π.

Changing the value of constant B

I am now going to change the values of B in the equation y= sin(Bx) to see what affect it has on the base curve.

Y=sin (3x)


Figure 11

Figure 11 shows that the amplitude, maximum and minimum values have the same value as the curve y=sinx, i.e  1 and -1. The period of y=sin3(x) has decreased from 2 π to π/3. It is also noticed that increasing the value of ‘B’ to 3, the curve repeats itself three times within the period f 2 π. So this shows that large values for ‘B’ have a smaller period but a larger frequency. So this shows that ‘B’ affects the period which affects the frequency of the equation.

Y=sin (-3x)                                                                                                


Figure 12

Figure 12 shows that the amplitude and maximum value remain 1 while the minimum value remains -1. And that the period also decreased from 2 π to π /3. Once again using the trace option on the graphing calculator, we notice that using a negative value inverts the curve.

Y= sin (0.25x)


Figure 13                                                Figure 14

...read more.


Y=sin (x)+ 2/5


Figure 26

Figure 26 shows my prediction is correct.

After examining what happens when changing all values in the equation, y= A sin B (x-C) +D, I am now going to predict what changes will occur is I used the equation y= 5 sin -2 (x-1) + ¾. I predict that the maximum value will change to 5, the minimum value will change to -5 and the amplitude will change to 5. The base curve is inverted because the ‘B’ value is a negative value and the period of the curve is decreased to π which increases the frequency to 2. The base curve also shifts to right by 1 unit and shifts vertically upwards by 0.75 (changing the maximum value to 5.75 and the minimum value to -4.25).


Figure 27


Figure 28                                                        Figure 29

Figure 27 above shows that my prediction is correct. Figure 28 proves shows that my prediction about the maximum value being 5.75 is correct. And Figure 29 using the trace button shows that my prediction about the curve having a phase shift to the right by one unit.

...read more.

This student written piece of work is one of many that can be found in our International Baccalaureate Maths section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Maths essays

  1. LACSAP's Functions

    - 2(6 - 2) = 13 3 21 ( (6+1)C2) - 3(6 - 3) = 12 4 21 ( (6+1)C2) - 4(6 - 4) = 13 5 21 ( (6+1)C2) - 5(6 - 5) = 16 1, 21/16, 21/13, 21/12, 21/13, 21/16, 1 The seventh row would be: Element Number Numerator Denominator 0 28 ( (7+1)C2)

  2. In this essay, I am going to investigate the maximum number of pieces obtained ...

    That is, by the principle of mathematical induction. T (n) is true. Now we try to rewrite the formula in the form P=Y+X+S where Y is an algebraic expression in n: n 1 2 3 4 5 S 2 3 4 5 6 n 1 2 3 4 5 R

  1. Population trends. The aim of this investigation is to find out more about different ...

    From graphing the model and trying to find a value for I found out that the closest the line can get to the points is when is equal to 0.026 and even when it is that close to the data it still has some gaps between the points and the line itself.

  2. Mathematics Higher Level Internal Assessment Investigating the Sin Curve

    First of all we examine the equation and identify the different variables. In this equation and . This means that the amplitude of the graph would be , causing the original curve to be stretched inwards, whereas the period of the new curve would be .

  1. Function Transformation Investigation

    * So for the moment, adding or subtracting a number to a function's output or input has translated it horizontally by adding or subtracting to the input, and vertically by adding or subtracting to the output. The translation compared to the original function can be predicted by this method: Will be a horizontal translation, right, by -a.

  2. Analysis of Functions. The factors of decreasing and decreasing intervals (in the y ...

    In power functions when the degree are positive integers then the function is subjective because as we can see in the graph there is a many to one relation. But in the case when the degrees of the function are negative integers, the functions turn to be bijective because there

  1. Shady Areas. In this investigation you will attempt to find a rule to approximate ...

    (3.64 + 4.0) = 0.764 TA= AA + AB + AC + AD + AE TA= 0.604 + 0.62 + 0.652 + 0.7 + 0.764 TA= 3.34 With the help of technology, create diagrams showing and increasing number of trapeziums. For each diagram, find the approximation for the area.

  2. The investigation given asks for the attempt in finding a rule which allows us ...

    h=âxn=b-an From the previous question, the values in both first and last based are used twice.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work