Processing raw data
Calculation of average S of oscillate 20 period
(T1+T2+T3+T4)/4
(8.8011+8.6011+8.6011+8.8010)/4
8.7011s
Calculation of Oscillate 1 period when X = 0.20m
(Average period T)/ 20
(8.7011)/20
0.44s
Presenting processed data
Calculate of Uncert. Of period T when X = 0.20m
(Highest T – lowest T)/(Highest T)
(8.8011 – 8.6011) / (8.8011)
0.023
% error
T2 = [(16π2M)/(bd3E)]
Find E by using T = 0.44, M = 51.4, b = 1.0, d = 0.1
Then 0.442 = [(16 X 3.142 X 51.4) / (1.0 X 0.13 X E)]
0.19 = [8108.54] / [0.001 X E]
E = 4.27 X 107 ±0.02405
This is a graph of relationship between oscillation and distance
Conclusion
From the physics book the term stiffness mean rigidity, the stiffness of steel in theory is 2.1 X 109, my result is 4.27 X 107, compare the theory stiffness than the result stiffness is totally different, and in the graph I can tell that when X increase, the oscillate time increase, I can tell X is proportional to the oscillate time.
Evaluating procedure
- If the surface is not horizontal, when measuring the oscillations of a hacksaw blade may get unreliable result.
- I don’t have enough time to measure the data when X = 0.14 and 0.13m, because I need to find a suitable wood for clamp my hacksaw blade, this may affect my result.
Improving the investigation
- Use a spirit level to measure the surface to be horizontal
- I may decrease one trial for reduce the time that I had lost
