• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
5. 5
5
6. 6
6

# Mechanics Coursework

Extracts from this document...

Introduction

Mechanics Coursework

Formulating my Model

My task is to produce a strategy necessary for scoring a basket in basketball. I shall investigate the effects of throwing the ball at different angles and ascertain the ideal angle for scoring a basket. In addition, I shall investigate what would be the best angle for me to throw the basketball rather than just the basketball player as the angle will be different as I am much shorter than a basketball player. I will model the motion of the ball as it leaves the hands of the basketball player and falls through the hoop. I will model the basketball as a particle.

Basketball is a ball game where if a free throw is taken a player will try and shoot a hoop from the free-throw line which is 4.6[1]m from the backboard of the hoop. The centre of the hoop is then 38[2]cm from the backboard. Therefore, the centre of the hoop is 4.22m from the free-throw line.

Middle

ax = 0ms-1 and ay = -9.8ms-1. sx = 4.22m. sy = height of basketball hoop – height of player.

sy = 3.05 – 1.98

sy = 1.07m

The five constant acceleration equations are:

v = u + at

s = ½ (u + v)t

s = ut + ½ at2

s = vt – ½ at2

v2= u2 + 2as

Variables are:

u, initial velocity, ms-1

v, final velocity, ms-1

t, time, s

All my measurements are accurate to 3 significant figures

Analysing my Model

The initial angles I shall use in my equations will be: 20°, 30°, 40°, 50°, 60°, 70°, and 80° degrees.

Once I have used these angles to discover whether the basketball falls through the hoop or not I shall narrow the range of angles e.g. 50°, 55°, 60°.

Model

When a particle moves in projectile motion its displacement and velocity are written as components.

The displacement of the particle in the x and y direction can be found from the constant acceleration equation

s = ut + ½ at2

Conclusion

a) in the x direction is 0 as we are ignoring any effects such as wind which could cause horizontal acceleration.

The velocity components of the particle are found using the constant acceleration equation

v = u + at

When we use this equation to find the velocity in the y direction it is written

vy = usinθ gt

When we use the equation v = u + at to find the velocity in the x direction it is written

vx = ucosθ

To summarise:

 Vertical Displacement Horizontal Displacement s = ut + ½ at2 s = ut + ½ at2 y = utsinθ – ½ gt2 x = utcosθ Vertical Velocity Horizontal Velocity v = u + at v = u + at vy = usinθ –gt vx = ucosθ

The next step in my investigation is to isolate the variables u, v and t (initial velocity, final velocity and time) onto one side of an equation so their values can be found.

This can be done through substitution: where one equation is substituted into another.

Firstly, I shall form an equation that isolates the initial velocity (u).

-  -

[1]

[2]

[4] This was an average based on the heights of one basketball team found on the website http://www.tigers.com.au/articles/nbl/018.php

This student written piece of work is one of many that can be found in our AS and A Level Mechanics section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related AS and A Level Mechanics essays

1. ## Localization of Motion Perception the Cortex

Area MT contains a complete representation of the contralateral visual field. Receptive field size increases linearly with eccentricity and is about ten times larger than in striate cortex, suggesting a significant convergence of inputs. The area is organized in a columnar fashion with blocks of cortical tissue containing similar directional selectivity.

2. ## One Dimensional Motion.

The program took readings of distance at 0.02 seconds for approximately 1.6 seconds. After the program executed a basketball was thrown in the air above the sensor and caught after 1.6 seconds. The test was repeated many times because the tester's hands would get in the way of the reading.

1. ## This essay neither examines a mathematical equation, nor does it analyze a distinguished mathematician. ...

When looked into a bit more deeply, they're mind-boggling as well as difficult to explain. And when closely analyzed, they are rather confusing and illogical. These have baffled many mathematicians. Greeks, who had no concrete understanding of convergence or infinity, found such reasoning incomprehensible.

2. ## Understanding Motion I &amp;amp;#150; Distance and Time

select the name of the display from the list at the end of the Display menu.

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to