GCSE Chemistry Coursework
Aim: to find out how changing the concentration of Sodium Thiosulphate in a sodium thiosulphate and hydrochloric acid solution effects the reaction rate.
Planning the experiment.
Apparatus: Conical flask
Paper with a cross on
35ml of Hydrochloric Acid
245ml of Sodium Thiosulphate
2 Measuring cylinders
180ml of tap water
Stopclock
Prediction: I predict that the more sodium thiosulphate in the solution, the faster reaction rate will be. This is because the solution must be concentrated so that bonds can be broken quicker. The more collisions in a given time, the faster the reaction will be. The reactants must hit each other hard to break bonds so this is why the solution must be very concentrated. Not all the collisions result in bonds breaking but the higher the concentration then the more collisions there will be and so there will be a higher chance of more collisions happening.
Planned method: We had done preliminary work which I have included the results from in the evaluation section. In this experiment the variable is going to be sodium thiosulphate. I am going to start off with 65cm3 of sodium thiosulphate, 5 cm3 of hydrochloric acid and no water in a conical flask. When I add the acid to the flask, I will start the stopclock and put the flask on top of the piece of paper with a cross on it. When the cross can no longer be seen, I will stop the stopclock,
These are the concentrations I will use in the experiment:
Sodium Thiosulphate
Water
Hydrochloric Acid
65
0
5
55
5
5
45
5
5
35
25
5
25
35
5
5
45
5
5
55
5
All of these quantities are measured in cm3. Sodium Thiosulphate and water are the variables. The amount of hydrochloric acid in the solution stays the same so that it is a fair test. This is one of the constants in the experiment and by keeping it the same, it makes the results more accurate. Another constant in the experiment is temperature and we did nothing to the temperature so the experiment was at room temperature, which stayed roughly the same throughout the experiment. To make sure it is also a fair test I am going to repeat the experiment three times and ten find the average time. This is a more reliable result because there could be some anomalous results that I can see more easily when I have a set of three results and pick them out of my results so that they won't effect the conclusion. Using the average time I will then find the reaction rate.
Aim: to find out how changing the concentration of Sodium Thiosulphate in a sodium thiosulphate and hydrochloric acid solution effects the reaction rate.
Planning the experiment.
Apparatus: Conical flask
Paper with a cross on
35ml of Hydrochloric Acid
245ml of Sodium Thiosulphate
2 Measuring cylinders
180ml of tap water
Stopclock
Prediction: I predict that the more sodium thiosulphate in the solution, the faster reaction rate will be. This is because the solution must be concentrated so that bonds can be broken quicker. The more collisions in a given time, the faster the reaction will be. The reactants must hit each other hard to break bonds so this is why the solution must be very concentrated. Not all the collisions result in bonds breaking but the higher the concentration then the more collisions there will be and so there will be a higher chance of more collisions happening.
Planned method: We had done preliminary work which I have included the results from in the evaluation section. In this experiment the variable is going to be sodium thiosulphate. I am going to start off with 65cm3 of sodium thiosulphate, 5 cm3 of hydrochloric acid and no water in a conical flask. When I add the acid to the flask, I will start the stopclock and put the flask on top of the piece of paper with a cross on it. When the cross can no longer be seen, I will stop the stopclock,
These are the concentrations I will use in the experiment:
Sodium Thiosulphate
Water
Hydrochloric Acid
65
0
5
55
5
5
45
5
5
35
25
5
25
35
5
5
45
5
5
55
5
All of these quantities are measured in cm3. Sodium Thiosulphate and water are the variables. The amount of hydrochloric acid in the solution stays the same so that it is a fair test. This is one of the constants in the experiment and by keeping it the same, it makes the results more accurate. Another constant in the experiment is temperature and we did nothing to the temperature so the experiment was at room temperature, which stayed roughly the same throughout the experiment. To make sure it is also a fair test I am going to repeat the experiment three times and ten find the average time. This is a more reliable result because there could be some anomalous results that I can see more easily when I have a set of three results and pick them out of my results so that they won't effect the conclusion. Using the average time I will then find the reaction rate.
