Finding our how much acid there is in a solution.

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Finding our how much acid there is in a solution.

Results table

Titration

Rough

2

3

Initial burette reading

0.00 cm3

1.00 cm3

0.00 cm3

1.10 cm3

Final burette reading

1.00 cm3

21.90 cm3

1.10 cm3

22.10 cm3

Titre

1.00 cm3

0.90 cm3

1.10 cm3

1.00 cm3

Average titre = 11.0 cm3

Equation of reaction: Na2CO3 (aq) + H2SO4 (aq) H2O (l) + CO2 (g) + Na2SO4 (aq)

So, one mole of sulphuric acid reacts with one mole of sodium carbonate to form water, carbon dioxide and sodium sulphide.

In the sodium carbonate solution there was 1.06g of sodium carbonate made up to volume of 100cm3 with distilled water.

Na2CO3

Na = 23* 2 = 46g

C = 12 * 1 = 12g

O = 16* 3 = 48g

+106g

mole of Na2CO3 = 106g

We used 1.06 g in our solution, 1.06/106 = 0.01 moles

so, 0.01 moles of Na2CO3 in 100cm3

In each experiment we use 10cm3, so this contains 0.001 moles of Na2CO3

Since we know that the volumes of the two solutions need to be approximately the same for the two solutions to react we know that the sulphuric acid must have approximately 0.001moles in 11cm3.

Sulphuric acid = 0.001 moles in 11.00cm3

From this we can work the concentration of the sulphuric acid to be:

1.00/1000= 0.011 (changing cm3 to dm3)

0.001/0.011 = 0.09 mol/dm3 (number of moles/volume)

The results and calculations clearly show what I believe to be an accurate concentration of sulphuric acid. I carried out the experiment as stated in my method 3 times after doing a rough test. This rough test was not included when I worked out my average titre. All my results were within 0.2cm3 of each other, which I accept to be a reasonable degree of accuracy.
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The measurements I took from the burette were only to two decimal places as this was all my equipment would allow. I think this delivers a good degree of accuracy but could be more accurate with more specialised equipment.

Errors almost certainly have occurred in my results, mainly human error but some also by errors in my procedure, technique and equipment have caused these. My reading of the meniscus in the burette could have caused some of the error, if I was not always careful. I could accurately read my burette to two decimal places, with the ...

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