To investigate how different molar concentrations of a salt solution affects osmosis in equal segments of a potato.

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Gail Wingham

Biology Sc1 – Osmosis Experiment in Potatoes

Aim:

To investigate how different molar concentrations of a salt solution affects osmosis in equal segments of a potato

Background Knowledge:

Osmosis is the movement of water molecules from a more dilute solution to a more concentrated solution through a partially permeable membrane. A partially permeable membrane is something that can only let small molecules of substances pass through and not larger ones (for example the wall of the small and large intestine is a partially permeable membrane because it lets smaller molecules such as amino acids and glucose though but does not let the larger chains of molecules through such as starch or fat).

In relevance to my experiment, the tiny spacing in between the membrane of a potato will allow the small molecules of water to pass through into the potato tissue but the rate at which it does this depends on the concentration gradient of both substances. When the water concentration in the potato tissue is lower than that of the surrounding solution it will allow for more water molecules to pass through and therefore there will be an increase in mass. Following this; if the concentration in the tissue is higher than that of the surrounding solution then the water molecules inside the potato will diffuse out causing a decrease in mass in the potato. Similarly, if the concentrations of both substances are (almost) equivalent then the change in mass is not very apparent because the movement of diffusion between the two substances is very minimal.

Prediction:

From my background knowledge I can predict that because the concentration of water molecules in the potato will be constant it means that it is the concentration of the solution it is put in that affects the rate of osmosis.

In relation to that it means that the higher the concentration of water molecules in the solution the greater the increase in the mass the segment of potato will have. This is because the movement of osmosis moves from the more diluted solution (more water) to the more concentrated solution (less water) and so as more water diffuses into the potato the more the potato’s mass will increase. In turn, this means that the solution with the lowest concentration of water in it have the reverse effect on the potato which will reduce in mass. This behaviour is due to the fact that if the solution around the potato is very concentrated and has little water then the water particles will diffuse from the potato which is of a lower concentration and into the solution.

The highest possible concentration of water I can obtain is in distilled water and so the segment of potato in this solution should have the greatest gain in mass. The lowest concentration of water I can obtain in this experiment is one mole of salt solution and so the potato in this solution, I predict, will have the greatest loss in mass.

I am yet to decide the range of my data; this will be decided during my preliminary test but I will imagine that the range will be along the lines of 0mol, 0.2mol, 0.4mol, 0.6mol, 0.8mol and 1mol. In these circumstances I predict that the difference between each mass in the different solutions will be reasonable small, depending on the time allowed to diffuse but I am going to wait until I have done my preliminary test so that I can make further predictions with the data I obtain.

The behaviour of the rate of osmosis will affect the appearance of my graph. My dependant data is the molar (or concentration) of each solution and my independent data is the change in mass and because I have predicted that as the concentration of my solutions increase the percentage mass gain will decrease and so my graph should look similar to the graph below.

The reason that it appears this way is because when the solution is weaker there are more water particles in the given volume and so more water particles can be transferred through the semi-permeable membrane in the time available because of the kinetic energy moving the particles around. The reason that the percentage mass increase falls into negative numbers is because after an (unknown) molar in the solution the concentration of water particles in the potato becomes greater than that of the solution and so these particles with then transfer into the solution.

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Variables:

There are a variety of factors that could affect that accuracy and even outcome of the data I collect and so I must consider each variable and how and why I need to control it. 

One of the most blatant of these is the size of the potato pieces. This needs to be measured as accurately as possible with a sensitive scale so as to record the mass losses and gains in each segment. Also the type of potato I use should be the same because different types of potatoes have different concentrations of water in them ...

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