Determining the Acceleration Due to Gravity

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Determining the Acceleration Due to Gravity (g)

Apparatus:

* Clamp and Stand

* Light gate

* Power supply

* Data logging terminal

* Computer

* Pendulum bob

* String

* 2x small flat pieces of wood

* Metre rule

* Vernier Scales

* Pen

* Card

* Weights

* Scissors

* Blue tack

Theory:

Gravity is a force of attraction between all objects. This attraction is proportional to the mass of the objects and inversely proportion to the distance between their centres. For a notable force the mass must be large. The earth has a great enough mass to show a measurable force of gravity. This is the force that attracts everything towards the centre of the earth. The force of attraction is greater for each mass, using this equation:

F=mg

Where g is the force of gravity. Force is related to acceleration and mass using this equation:

F=ma

Simultaneously equating these equations gives us:

mg=ma

g=a

Therefore g in newtons is the same value as the acceleration due to gravity in metres per second.

The simplest way to measure g is to drop a mass and measure it's acceleration. We can find acceleration, by finding the change in velocity over a certain period:

a=(v-u)/t

Where velocity is measured over a distance of 5cm, this will be the average velocity. I will consider this velocity to occur in the middle of the 5cm distance. As the object is accelerating, this is unlikely to be the place of average velocity, it is more likely to be after this but it is extremely difficult to determine the exact location. I think this method would be less accurate as it is hard to measure acceleration accurately using just one light gate. This is because the average speeds are used in the equation and not the exact. As the formula we use is change in velocity divided by the time taken for this change. Also this would be affected by air resistance. This will reduce acceleration and give a lower value for g. The air resistance increases as speed increases and so is proportional to the speed. This would mean that the object must be moving slowly to reduce the effects of air resistance.

Another method would be to use a pendulum. Pendulums perform simple harmonic motion (SHM). This is when a mass oscillates freely about a fixed central position. Once it has started to swing there is a restoring force to bring it back to it's equilibrium this restoring force is proportional to the distance from equilibrium, i.e. at the height of it's swing it has the greatest restoring force, and at it's equilibrium position is has no restoring force. Once the mass has reached equilibrium it is travelling at it's greatest speed and so has the greatest momentum, the restoring force is at a minimum so the pendulum will continue past the equilibrium, and so the pendulum will continue to oscillate like this. All energy in a pendulum system is conserved, either in the form of potential energy or kinetic energy. At its highest point (furthest away from equilibrium) it has no kinetic energy, but full potential energy. This potential energy is equal to the energy put into the system (the energy used to start the swing). At the equilibrium position all the energy is kinetic and so the mass is moving at the greatest velocity. The energy is therefore never lost.

energy in an shm system

*from Physics 2 Cambridge

This is for an undampened system, but our system will be slightly damped by air resistance, we are using a small bob and a thin string so this resistance will be negligible. We will not try to measure the air resistance as in theory during SHM, damping will only affect the amplitude and not the frequency.
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The forces acting on the pendulum:

A bob A of mass m hangs from a fixed point B with a string of length l. The string makes an angle of ? with the normal. The pendulum oscillates about the equilibrium O. The path of the bob A creates an arc of length x

The forces on A are it's weight mg and tension P. Resolving the weight of A we get a component acting on the tangent to the arc mgsin? this is the restoring force. We also a component acting along the normal to the ...

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