Determine the concentration of a limewater solution

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AIM: To determine the concentration of a limewater solution.

You have been provided with 250cm3 of limewater, which contains approximately 1g dm-3 of calcium hydroxide. Hydrochloric acid is also available, which has a concentration of exactly 2.00 mol dm-3.

In order to determine the concentration of the limewater solution I will have to carry out a titration experiment between the acid being hydrochloric acid, HCl and the base being the limewater, Ca(OH) 2.  

However before continuing on with the titration you need to dilute the HCl acid since it is too concentrated to use. In order for you to do this you will need to work out the concentration of Ca(OH) 2.

Balanced Equation of the titration:

    2HCl           +      Ca(OH)2      CaCl2     +     2H2O

 2 moles                  1 mole

2 mol dm-3                 ?

Ca(OH)2 is 1g dm-3= 1 gram per 1dm3

No. of moles in Ca(OH)2 = Mass / Relative formula mass (RFM)

                                = 1 / 74

                                = 0.0135 moles

Concentration of Ca(OH)2 = No. of moles / Volume

                                  = 0.0135 / 1

                                  = Ca(OH) 2 mol dm-3  

Now that you have worked out the concentration of the lime water solution you can continue with the dilution process of HCl acid. In order to do this you will need to select a suitable concentration for the HCl acid to be diluted to.

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As we already know according to the balanced equation 1 mole of Ca(OH)2 reacts with exactly 2 moles of HCl, so you should try and make HCl two times concentrated as the Ca(OH)2.

So in order to make HCl twice as concentrated as Ca(OH)2  you will do the following calculation: 0.0135 x 2 = 0.027 mol dm-3 . This means the 2 mol dm-3 will need to be diluted to 0.027 mol dm-3 however this is to difficult to measure so a better concentration to dilute HCl to would be 0.02 mol dm-3.

The dilution factor ...

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