# This investigation is an investigation to find the concentration of two unknown solutions, Na0H and HCl by titration.

by joshtinsley96hotmailcouk (student)

Titration of an unknown solution

Abstract

This investigation is an investigation to find the concentration of two unknown solutions, Na0H and HCl by titration. This titration was to calculate how much solution it took to neutralise a solution. From these results we could use the molarity to calculate the concentration of the solution. The concentration of HCl in this titration was 1.07mol/dm3 and the concentration for Na0H was 1.22mol/dm3.

Introduction

Two solutions of unknown concentration will be reacted with two known concentrated solutions. This investigation is being carried out to determine the unknown concentrations for both solutions, to determine this, two titrations will be carried out.

The first titration being carried out is between an alkali, which is Sodium Hydroxide (NaOH) with a known concentration of 0.1mol/dm3 and an acid, which is Hydrochloric Acid (HCl) with unknown concentration. The second titration is finding the unknown concentration of an alkali, which is Sodium Hydroxide (NaOH) by reacting it with an acid, Sodium Hydrogen Sulphate (NaHSO4) with a known concentration of 0.1mol/dm3.

The first step in carrying out this investigation was calculating the mass of the substances which needed to be dissolved in distilled water in each titration. To do this, the moles in the substances must be worked out by using the equation Moles=Molarity x Volume. Each titration shares the same molarity and volume, therefore the equations for both would be;

0.1X0.25=0.025 Moles

Using the equation, the number of Moles needed for each is 0.025. Therefore the first titration which uses Sodium Hydroxide will have 0.025 moles and the second titration which uses Sodium Hydrogen Sulphate will also have 0.025 moles.

Using the mole count for Sodium Hydroxide and Sodium Hydrogen Sulphate we can determine the mass needed for each titration. This is worked out by using this equation, Mass=Molecular Mass x Moles.I used the periodic table find the atomic mass of Sodium Hydroxide, Sodium mass is 23, Hydrogen is 1 and Oxygen is 16. Therefore the atomic mass needed for Sodium Hydroxide is 40 x 0.025= 1g. Next the mass of Sodium Hydrogen Sulphate needed will be 120 x 0.025=3g, meaning that 3g of Sodium Hydrogen Sulphate will be needed for the second titration.

Using the results from the calculations, the first titration will use 1g of Sodium Hydroxide diluted in 250ml of distilled water resulting in the concentration being 0.1mol/dm3. The second titration will use 3g of Sodium Hydroxide Sulphate diluted in 250ml of distilled water also resulting in the concentration being 0.1mol/dm3.

Aim

The aim of this investigation is to find the unknown concentration of two solutions by titration. The first being Hydrochloric Acid (HCl) and the second being Sodium Hydroxide (NaOH). The investigation will also determine the volume need to neutralise the solution of either the acid or alkali.

Method

In ...