Beyond Pythagoras.

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Beyond Pythagoras

      Having done Pythagoras’ theorem in detail in and out of class, I am familiar with what his theorem states. I can show that his theorem works on the following triples using details and substitution.

The 3-4-5 triangle

                                         (3) 2 + (4) 2 = (5) 2

                                    => 9 + 16 = 25                        TRUE: 3-4-5 is a Pythagorean triple.

 The 5-12-13 triangle

                                         (5) 2 + (12) 2 = (13) 2

                                    => 25 + 122 = 169                TRUE: 5-12-13 is a Pythagorean triple.

The 7-24-25 triangle

                                          (7) 2 + (24) 2 = (25) 2

                                     => 49 + 576 = 625                 TRUE: 7-24-25 is Pythagorean triple.

      During the methods, I have observed the following about the numbers and triangles used so far:

  • The longest side (hypotenuse) is related to the middle length side. i.e. middle side + 1
  • The shortest length side is always an odd number follow the pattern 3-5-7…
  • The middle length side is even and a multiple of 4.

      I have also been asked to find the area and perimeter of the triangles done in the last exercise. The formula for finding the area of any triangle is ½base X height or base X height.                                                                                                                                                                     2                                                                                                                                         2                                          

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Area and perimeter of the triangle 3-4-5

Area = ½ * 3 * 4      Perimeter = 3 + 4 + 5

        = 6 units2                          = 12 units

        

Area and perimeter of the triangle 5-12-13

Area = ½ * 5 * 12      Perimeter = 5 + 12 + 13

        = 30units2                        = 30units

Area and perimeter of the triangle 7-24-25

Area = ½ * 7 * 24      Perimeter ...

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