Borders Coursework

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Candidate no. 1874                                                                                       Saagar Kotecha 11SZ

Borders Coursework

Part 1:

Aim: 

I shall investigate a set pattern of squares and shall look at how the total number of squares increases each time the geometric shape gets larger. I shall then look at the relationship between the increase in size of the geometric shape and the number of additional squares that need to be added to cause this increase.

Prediction:

As the cross increases in length and width, I predict more squares will have to be added. I predict that the number of white squares should be directly proportional to the size of the cross. This is because as a two dimensional shape gets larger, its perimeter increases. Also, I predict that the total number of squares will increase in proportion to n2. This is because as the length of the two dimensional shape increases, its area increases in proportion to length2.

Finding the n th term for black squares:

Formula:  an² + bn + c

1                1                5                13                25                41

         0                     4                 8                 12                16

                   4                         4                      4                    4

Formula:                 + bn + c

a = 2nd difference

                2

a =   4/2

   

   =  2

   .

.    .       =     2n² + bn + c

Formula: 2n² +                 + c

 1                1                5                13                25                41

2×(1²)                   2×(2²)                   2×(3²)                       2×(4²)                    2×(5²)                 2×(6²)

= 2                     = 8                           = 18                       = 32                    = 50                         =72

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1-2                     1-8                        5-18                       13-32                    25-50                 41-72

= -1                    = -7                = -13                     = -19                   = -25                 = -31

            -6                        -6                    -6                           -6                           -6

   .

.    .       =     2n² – 6n + c

Formula: 2n² – 6n +

When n = 1

   2 × (1²) – (6 × 1)

= 2 – 6

= - 4 + ? = 1

= - 4 + 5 = ...

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