2
If you look at my table this correct.
Now I’m correct with my formula I can find area of a shape of any size as long as there is 1 dot inside.
E.G
N= 100 A=100 =50cm2
2
Now I have investigated shapes with 2 dot inside I will put my answers into a table.
- After creating a table 3, I have noticed a pattern in the area column.
- The pattern is going up in ½ cm2 each time a dot is added to the edge.
By looking at the pattern I have created formula in both words and algebra.
Area = number of dots +1 A= N +1
- 2
To show I’m right:
When =N=6 A= 6+1 = 4cm2
2
If you look at my table it is correct.
Now I’m correct with my formula I can find area of a shape of any size as long as there are 2 dots inside.
E.G
When =N=80 A=80 +1 =40+1
- =41cm2
After completing all the diagrams, tables and formulas I have noticed a pattern between the three formulas:
I have put all the formulas into a table:
A=N-1 0 dots inside
2
A=N+0 1 dot inside (I have added the 0 just to show the pattern works)
2
A=N+1 2 dots inside
2
As you can see the formulas are going up in 1, every time the dots inside the shape are increased.
By doing this I have created 1 formula which is the three formulas combined as 1
This is:
Area= number of dots + dots inside -1
2
A=N + D -1
2
Now I’m correct with my formula I can find area of a shape of any size with any number of dots inside and joint.
EG:
When= N= 12 D= 5 A=12+5-1 = 6+5-1=10cm2
2
Calculating the area of a shape
In this project I have investigated the area of shapes; I have investigated shapes with 3,4,5,6 and 7 dots joined and I will look at building up the dots inside the shapes later on.
After drawing the shapes I have noticed that, shapes with the equal number of dots have the same area, this can be seen on the previous diagram pages. So from now on I will only draw 1 of each type of diagram.
I will now put all of my results for no dots inside into a table.
Table 1
- After creating a table 1, I have noticed a pattern in the area column.
- The pattern is going up in ½ cm2 each time a dot is added to the edge.
- By looking at the pattern I have created formula in both words and algebra:
Area = the number of dots - 1 A=N – 1
A= Area 2 2
N= Number of dots
To prove I’m right
When N = 3 A=3 - 1 = 1 ½ -1 When N=4 A=4 -1 =2-1
2 = ½ cm2 2 =1 cm2
When N=5 A=5 -1 = 2 ½ -1 When N=6 A=6 -1 =3-1 When N=7 A=7 – 1 =3 ½ -1
2 = 1 ½ cm2 2 =2cm2 2 =2 ½ cm2
If you look at my table you will see this correct.
Now I know I am definitely correct with my formula I can find area of a shape of any size as long as there are no dots inside and this is shown on back of the diagram sheet.
E.G
N=10 A=10 – 1 = 5 - 1
2 = 4cm2
Now I have investigated shapes with 1 dot inside I will put my answers into a table.
Table 2
- After creating a table 2, I have noticed a pattern in the area column.
- The pattern is going up in ½ cm2 each time a dot is added to the edge.
By looking at the pattern I have created formula in both words and algebra.
A= area area= the number of dots A=N
N=number of dots 2 2
To show I’m right:
When N=3 A= 3 =1 ½cm2 When N=4 A=4 =2cm2 When N=5 A=5 =2 ½cm2
2 2 2
When N=6 A=6 =3cm2 When N=7 A=7=3 ½cm2
2 2
If you look at my table this correct.
Now I’m correct with my formula I can find area of a shape of any size as long as there is 1 dot inside and this is shown on back of the diagram sheet.
E.G
N= 10 A=10 =5cm2
2
Now I have investigated shapes with 2 dot inside I will put my answers into a table.
Table 3
- After creating a table 3, I have noticed a pattern in the area column.
- The pattern is going up in ½ cm2 each time a dot is added to the edge.
By looking at the pattern I have created formula in both words and algebra.
Area = number of dots +1 A= N +1
- 2
To show I’m right:
When N=3 A=3+1 =2 ½cm2 When N=4 A=4 +1 =3cm2 When N=5 A=5 +1 =3 ½ cm2
2 2 2
When N=6 A=6+1=4cm2 When N=7 A=7+1=4 ½cm2
2 2
If you look at my table it is correct.
Now I’m correct with my formula I can find area of a shape of any size as long as there are 2 dots inside and this is shown on the diagram sheet.
E.G
When =N=10 A=10 +1 =5+1
- =6cm2
After completing all the diagrams, tables and formulas I have noticed a pattern between the three formulas:
I have put all the formulas into a table:
Table 4
A=N-1 0 dots inside
2
A=N+0 1 dot inside (I have added the 0 just to show the pattern works)
2
A=N+1 2 dots inside
2
As you can see the formulas are going up in 1, every time the dots inside the shape are increased.
By doing this I have created 1 formula which is the three formulas combined as 1
This is:
A=Area D=Dots inside N=number of dots joined
Area= number of dots + dots inside -1
2
A=N + D -1
2
Now I’m correct with my formula I can find area of a shape of any size with any number of dots inside.
EG:
When= N= 10 D=2 A=10+2-1 = 5+2-1=6cm2
2
Now I will show some examples for the final formula for 0 dots, 1 dot and 2 dots in side on some of the past diagrams I have drew , but with the final formula not the individual formulas.
EG 1:
When N=5 D=0 A=5 +0 - 1 =1 ½ cm2
2
EG 2:
When N=7 D=1 A=7 +1-1 = 3 ½ cm2
2
EG 3:
When N=3 D=2 A=3 +2 -1 =2 ½ cm2
2
Mathematics
Coursework
Area of a shape
Leigh Bevan