An investigation into the effect of changing concentration of a substrate on an enzyme controlled reaction.

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Sam Daniels                04/05/2007

Sam Daniels

Biology Coursework

An investigation into the effect of changing concentration of a substrate on an enzyme controlled reaction


Aim

        My aim is to plan, investigate, analyse and evaluate the effect of varying the concentration of hydrogen peroxide in the reaction with potato catalase by measuring the Volume of oxygen produced.

Introduction

        Catalase releases oxygen from hydrogen peroxide (H202) and is used in the making of foam rubber from latex. Many kinds of enzymes are found in each cell but because they are used over and over there may be only a small amount of each enzyme present.  Catalase is found in both plant and animal tissues. In animal cells, catalase is found in liver cells, as the liver is the organ responsible from removing toxic wastes from the body. Such wastes include alcohol and hydrogen peroxide. Catalase accelerates the breakdown of hydrogen peroxide (H202) into water (H2O) and oxygen (O2).  The chemical equation for this reaction is:

 2H2O2                 Catalase          2H2O + O2.

Enzymes are biological catalysts; they speed up chemical reactions, which would otherwise be very slow and they are always proteins. Several factors affect the action of enzymes: salt concentration, pH, temperature (they are denatured by heating), poisons, radiation, the concentration of enzymes, and the concentration of the substrate. Enzymes can be used over and over again and they are specific in their action, as associated with the ‘lock and key hypothesis’. What this means is that each enzyme controls one particular reaction, or type of reaction. For example, maltase will only act on maltose. The collision theory will also have an effect on the investigation due to the concentration of the hydrogen peroxide being increased.

Variables

        In my investigation there are a range of variables. The constant variables will be the temperature of the water in the beaker, the temperature of the hydrogen peroxide and of the catalase, (the warmer the enzyme is the quicker the reaction takes place (collision theory) until it reaches its peak and then denatures. And the colder it gets, the slower the reaction takes place), the concentration of the catalase, the surface area of the potato chips (catalase), the time for the reaction to occur, and the Volume of hydrogen peroxide used. The dependent variable will be the Volume of oxygen gas produced and the independent variable will be the concentration of the hydrogen peroxide.


Fair Test

        I want my experiment to be a fair test. This is why I am including a ‘control’ experiment, which will have the same amount of potato chips in a 0% concentration of hydrogen peroxide (pure water). Another example of a ‘control’ experiment would be no potato chips in pure hydrogen peroxide, but I will not use this ‘control’ because the hydrogen peroxide will decompose into oxygen and water on its own. The ‘control’ experiment will check that all of the oxygen produced has come from the reaction of the hydrogen peroxide with the catalase. The only change I will make is the concentration of the hydrogen peroxide because if I change any other variables I will not know which of them affected the results of the dependant variable, (oxygen gas).

Plan

        I will set up the apparatus as shown in the diagram on the next page. I will be given some potato cylinders, which have been extracted from the same potato by a cork borer. Then, on a white ceramic tile I will cut off the dead skin from the potato with a scalpel because the dead skin will not contain any catalase and so will not react. Then I will cut the potato cylinder into 1mm thick chips using a scalpel and a ruler, so the surface area of the chips are all the same to make it a fair test. Then I will fill a large beaker about ¾ full of water and also fill up a measuring cylinder and clamp it upside down, in the water so there is no air in it to contaminate the recording of the amount of oxygen produced. After the clamp stand, water beaker, potato and measuring cylinder are prepared and laid out correctly; I will start preparing the hydrogen peroxide. First I will use a pipette to suck up 10cm3 of H202 and then I will carefully drain the pipette into a reaction vessel making sure I do not drip any. This will make sure it is the full amount of H202 that is reacting with the catalase. Once everything is set, I will add 5 potato chips to 5ml of H202 all at the same time. As soon as the potato chips enter the H202, I predict that a reaction will start and so I will have to act quickly, but carefully to put the bung on the reaction vessel, block the top of the delivery tube so no gas escapes, and place it under the measuring cylinder in the water beaker. Only then can I allow the gas to escape because if the gas does escape, when I do actually start measuring it, I will record inaccurate results of the total gas produced. . I will quickly start the stopwatch and begin recording my data I will record the amount of oxygen in the measuring cylinder every 30 seconds.

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Prediction (Hypothesis)

I predict that the more concentrated the hydrogen peroxide is, the faster the rate of reaction of the hydrogen and the catalase will be, and the faster the oxygen will being given off. Also the rate of the oxygen being given off should be directly proportional to the concentration of the hydrogen peroxide. I also think that the collision theory will also have an effect on the investigation due to the concentration of the hydrogen peroxide being increased. The collision theory is the theory that a chemical reaction can only occur between particles when they ...

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