Comparing the enthalpy changes of combustion of different alcohols

Authors Avatar
Comparing the enthalpy changes of combustion of different alcohols:

Aim:

The aim of my investigation is to compare the enthalpy changes of combustion of two chosen alcohols from the given list displayed:

Alcohol name

Molecular formula

Structural formula

Methanol

CH3OH

Ethanol

C2H5OH

Propan-1-ol

C3H7OH

Butan-1-ol

C4H9OH

Propan-2-ol

C3H7OH

Butan-2-ol

C4H9OH

2-methylpropan-1-ol

C4H9OH

Alcohols are derivates of alkanes; they have similar structures but varying functional groups. In alcohols one of the hydrogen atoms, which is generally attached to one of the central carbons, is replaced by an -OH group (Hydroxyl group). This variation largely determines the behaviour of the members of this homologous series in certain reactions.

For example, Alcohols tend to have higher boiling points than the respective alkanes; this is because although the hydrogen bonds between the molecules are relatively weak, they are stronger than other attractive forces between covalent molecules.

I have chosen to compare the enthalpy change of combustion of Methanol, Ethanol Propan-1-ol and Butan-1-ol. This is because they are fairly commonly used, and a larger set of information is available about them.

During combustion, the two alcohols will burn in a plentiful supply of oxygen, and the products of the combustion will be carbon dioxide (CO2) and water (H2 O).

The elevated temperature will break the Hydrogen bonds that hold the molecule together, and new bonds between the atoms will form to give life to the new products.

I will now display the formula, which I am going to use to calculate the enthalpy change of combustion for each alcohol:

Q = mc ?t

Q= energy transferred

m= mass of the water being heated

c= specific heat capacity of water

?t= temperature change of the water

Prediction:

The alcohols, which I have decided to use for my experiment, are known as primary alcohols. The latter, are defined as alcohols in which the -OH group is attached to a carbon atom which is bonded to only one other carbon atom.

The oxidation of primary alcohols occurs in the following manner: Two hydrogen atoms are removed from the molecule. One is from the oxygen and the other is from the adjacent carbon atom, either one will do. Because the carbon atom involved in the reaction starts with two hydrogen atoms, it still has one hydrogen atom attached to it after the reaction is over. That makes the product an aldehyde instead of a ketone.
Join now!


Aldehydes are colourless, mobile and very volatile liquids. They are an intermediate between alcohols and acids; they differ in the sense that they have two less hydrogen atoms in their molecule.

I predict that the enthalpy change of combustion will increase following this pattern: Methanol?Ethanol?Propan-1-ol?Butan-1-ol. It is possible to see from the table I displayed at the start of the investigation that the number of carbon atoms in the molecule increases from Methanol to Butan-1-ol. If there's a bigger number of carbon atoms more energy will be required to break the initial bonds between the molecules. Therefore ...

This is a preview of the whole essay