Comparing the enthalpy changes of combustion of different alcohols:
Aim:
The aim of my investigation is to compare the enthalpy changes of combustion of two chosen alcohols from the given list displayed:
Alcohol name
Molecular formula
Structural formula
Methanol
CH3OH
Ethanol
C2H5OH
Propan-1-ol
C3H7OH
Butan-1-ol
C4H9OH
Propan-2-ol
C3H7OH
Butan-2-ol
C4H9OH
2-methylpropan-1-ol
C4H9OH
Alcohols are derivates of alkanes; they have similar structures but varying functional groups. In alcohols one of the hydrogen atoms, which is generally attached to one of the central carbons, is replaced by an -OH group (Hydroxyl group). This variation largely determines the behaviour of the members of this homologous series in certain reactions.
For example, Alcohols tend to have higher boiling points than the respective alkanes; this is because although the hydrogen bonds between the molecules are relatively weak, they are stronger than other attractive forces between covalent molecules.
I have chosen to compare the enthalpy change of combustion of Methanol, Ethanol Propan-1-ol and Butan-1-ol. This is because they are fairly commonly used, and a larger set of information is available about them.
During combustion, the two alcohols will burn in a plentiful supply of oxygen, and the products of the combustion will be carbon dioxide (CO2) and water (H2 O).
The elevated temperature will break the Hydrogen bonds that hold the molecule together, and new bonds between the atoms will form to give life to the new products.
I will now display the formula, which I am going to use to calculate the enthalpy change of combustion for each alcohol:
Q = mc ?t
Q= energy transferred
m= mass of the water being heated
c= specific heat capacity of water
?t= temperature change of the water
Prediction:
The alcohols, which I have decided to use for my experiment, are known as primary alcohols. The latter, are defined as alcohols in which the -OH group is attached to a carbon atom which is bonded to only one other carbon atom.
The oxidation of primary alcohols occurs in the following manner: Two hydrogen atoms are removed from the molecule. One is from the oxygen and the other is from the adjacent carbon atom, either one will do. Because the carbon atom involved in the reaction starts with two hydrogen atoms, it still has one hydrogen atom attached to it after the reaction is over. That makes the product an aldehyde instead of a ketone.
Aim:
The aim of my investigation is to compare the enthalpy changes of combustion of two chosen alcohols from the given list displayed:
Alcohol name
Molecular formula
Structural formula
Methanol
CH3OH
Ethanol
C2H5OH
Propan-1-ol
C3H7OH
Butan-1-ol
C4H9OH
Propan-2-ol
C3H7OH
Butan-2-ol
C4H9OH
2-methylpropan-1-ol
C4H9OH
Alcohols are derivates of alkanes; they have similar structures but varying functional groups. In alcohols one of the hydrogen atoms, which is generally attached to one of the central carbons, is replaced by an -OH group (Hydroxyl group). This variation largely determines the behaviour of the members of this homologous series in certain reactions.
For example, Alcohols tend to have higher boiling points than the respective alkanes; this is because although the hydrogen bonds between the molecules are relatively weak, they are stronger than other attractive forces between covalent molecules.
I have chosen to compare the enthalpy change of combustion of Methanol, Ethanol Propan-1-ol and Butan-1-ol. This is because they are fairly commonly used, and a larger set of information is available about them.
During combustion, the two alcohols will burn in a plentiful supply of oxygen, and the products of the combustion will be carbon dioxide (CO2) and water (H2 O).
The elevated temperature will break the Hydrogen bonds that hold the molecule together, and new bonds between the atoms will form to give life to the new products.
I will now display the formula, which I am going to use to calculate the enthalpy change of combustion for each alcohol:
Q = mc ?t
Q= energy transferred
m= mass of the water being heated
c= specific heat capacity of water
?t= temperature change of the water
Prediction:
The alcohols, which I have decided to use for my experiment, are known as primary alcohols. The latter, are defined as alcohols in which the -OH group is attached to a carbon atom which is bonded to only one other carbon atom.
The oxidation of primary alcohols occurs in the following manner: Two hydrogen atoms are removed from the molecule. One is from the oxygen and the other is from the adjacent carbon atom, either one will do. Because the carbon atom involved in the reaction starts with two hydrogen atoms, it still has one hydrogen atom attached to it after the reaction is over. That makes the product an aldehyde instead of a ketone.