Determine the relative formula mass and the molecular formula of succinic acid

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Experiment:

 To determine the relative formula mass and the molecular formula of succinic acid

Aim:

Using volumetric analysis, with a known standard solution of NaOH, to titrate a solution of succinic acid to determine its molar concentration and hence it’s molecular mass.

Principle:

Given that succinic acid is a dibasic acid with the molecular formula HOOC – (CH2) n - COOH where n is a number between 1 and 4 (both inclusive).

H2 A        +   2NaOH                 Na2A +        2H2O

1 Mole             2 moles

In the experiment a standard solution of succinic acid with a known gram – concentration is allowed to titrate to equilibrium with a convenient quantity of 25 cm3 of the standard solution of NaOH provided.

Assume that the concentration of standard solution of NaOH be 0.1M.dm-3

No. of moles of NaOH in 25 cm3 of the solution = 0.0025 moles

Since the mole ratio of acid : alkali is 1:2,

No. of moles of acid required to neutralize 25 cm3 of the solution of Na OH = 0.0025/2 =0.00125 moles

Assuming the n=3, Mr of succinic acid =132

Since Mr = m / M, the mass of succinic acid required = 132*0.00125 = 1.65g. So 1.65 g of succinic acid is dissolved in 250 cm3 of distilled water to make the standard solution of succinic acid.    

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(A) Preparation of a standard solution of succinic acid:

  • Take a clean dry weighing bottle and weigh the bottle.
  • Measure 1.65g of the solid succinic acid taken in the weighing bottle using a chemical balance (upto 2 decimal points).
  • Dissolve the solid in a beaker completely stirring with a glass rod with approximately 100 cm3 of distilled water.
  • Transfer the beaker contents into a volumetric flask of 250cm3.
  • Wash (*3) beaker and funnel to ensure all the dissolved solid reaches the flask.
  • Add distilled water to the volumetric flask directly until close ...

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