Individual investigation - Reaction to be studied Rate of reaction between propanone and iodine

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Reaction to be studied

Rate of reaction between propanone and iodine proceeds in acidic solution (H+ ions as a catalyst).

CH3COCH3 (aq)   +   I2 (aq)     →    CH3COCH2I (aq)   +   H+ (aq)   +   I  (aq)

           

Propanone                  Iodine                Iodopropanone                

I have to investigate:

  • The effect of changing the concentrations of the reactants (including the catalyst) on the rate of reaction.
  • The order of each reactant.
  • Therefore, find out the rate equation.
  • Different methods to see the effects on the rate of reaction.
  • The effects of temperature on rate of reaction.
  • Therefore, find out the activation enthalpy for the reaction.
  • The effect of other acidic catalyst on rate of reaction.
  • The effects of temperature with the new catalyst on rate of reaction.
  • Therefore, comparing the activation enthalpy with and without the catalyst.

CHEMICAL KNOWLEDGE:

Collision theory:

Different factors affect the rate of reaction such as:

  • Temperature
  • Catalyst
  • Concentrations of reactants

According to the collision theory, for a reaction to occur the reactant particles must collide. As the we increase the factors, the particles will collide more vigorously due to which the rate of the reaction increases. Different reactions can happen at different rates. Reactions that occur slowly have a low rate of reaction. Reactions that happen quickly have a high rate of reaction (reactant’s bond are broken faster and new bonds are made faster). But particles with only little energy will not react when they collide. Therefore, for a reaction to take place particles must collide with enough energy (Activation Energy).

  • Temperature:

As we increase the temperature, the kinetic energy of the particles increases so they collide more and vibrate more resulting increase in rate of reaction. Increasing temperature increases number of particles with minimum required activation energy.

The area under a curve shows the number of particles. At the higher temperature curve shifts to the right (which is T+t) and the number of particles increases with minimum required activation energy. Therefore, faster the rate of reaction.


  • Catalyst:

Catalyst is a substance that speeds up the reaction but chemically unchanged at the end of the reaction. Catalyst lowers the activation energy resulting increase in rate of reaction. Therefore, there are more numbers of particles (more collision) with minimum required activation energy.

  • Concentration:

As we increase the concentration of the reactants, the number of particles increases in a given volume. More number of particles means more number of collision resulting increase in rate of reaction. Therefore, at high concentration there are more number of particles with minimum required activation energy.

ARRHENIUS   EQUATION:

Arrhenius equation shows how rate constants vary with temperature and activation energy.

K= Rate constant where it only changes when temperature or the catalyst changes.

A= Frequency factor of collision and their orientation.

e= Mathematical number (value of 2.71828...).

EA= Minimum activation energy required for reaction to take place.

R= Gas constant (value of 8.31JK-1mol-1).

T= Temperature measured in Kelvin. For e.g.:  23.C = (23+273) K = 296 K

                                                        


EXPERIMENTAL KNOWLEDGE:

Titration:

        Titration is the method that is used to determine unknown concentration of reactant and will allow us to determine the precise endpoint of a reaction.

  • When taking reading using grading pipettes and burettes, we have to make sure that the readings is at eye level to reduce parallax errors.
  • Readings should always be taken from the bottom of the concave meniscuses.

  • A white tile should be place below the conical flask while titrating so that we can see the colour clearly.
  • To make experiment accurate, we have to rinse the burette or pipette with the solution with the solution that we are going to use.
  • When titrating, we have to perform certain process show below:
  • Use accurate grading pipette into the conical flask.
  • Rinse the burette using the known concentration of sodium thiosulfate (VI) and then fill the burette with sodium thiosulfate (VI).
  • From the burette slowly add the sodium thoisulfate (VI) to the conical flask containing test solution.
  • Add the starch indicator to the solution when the colour of the iodine starts to fades away.
  •  When the colour of the solution comes the end point (colourless) then stop adding the sodium thiosulfate (VI).
  • Repeat the above process until two titre as close about 0.1 cm3.
  • Use the value of the titre to find out the concentration of the solution.
  • Repeat the experiment for different time interval of the solution.
  • Plot the graph (concentration against time) and find the initial gradient.
  • Finally, find out the order of the reaction.

Calculating initial rate:

  • Draw a tangent at time = 0 where the gradient of the tangent is the initial rate.

Gradient=

Determining the order of the reaction:

One of the ways of finding out the order of the reaction is to draw the graph of rate against concentration or concentration against time.

For rate against concentration graph:

  • Zero order:  Rate must be constant with respect to the concentration of the solution where the gradient is zero

  • First order: Rate must be proportional with respect to the concentration of the solution.
  • Second order: Rate must be proportional with respect to the (concentration)2 because the rate against the concentration is not a straight line.
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For concentration against time graph:

  • Zero order:  Concentration must be proportional (inversely) to the time because the reactant is being used up and the gradient is constant.
  • First order: If the concentration is exponentially decreasing with respect to time, then the half life must be constant which tells us that the reaction is first order
  • Second order: If the concentration is exponentially decreasing with respect to time, then the half life must be greater than initial half lives which tell us that that reaction is second order.

MAKING STANDARD SOLUTION:

  • Zero ...

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