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Calculating Reaction Rate Between Sodium Thiosulphate and Hydrochloric Acid Coursework

In this experiment I will be seeing how the concentration of Sodium Thiosulphate, Na2S2O3, and Hydrochloric Acid, HCl, affects the rate of the reaction. In this reaction the solution turns milky yellow as sulphate is displaced and forms a solid precipitate.

Na2S2O3 (aq)  +  2HCl (aq)   ---------->     2NaCl (aq)  +  H2O (l)  +  SO2 (aq)  +  S (s)

The Rate of a reaction can be represented as:     Δconcentration     and so is the time

                                                                  Δ time

taken for the reactants to be used up. Therefore I will be investigating if either:

                                       Rate [Na2S2O3]x          or/and      Rate  [HCL]Y  

where X and Y are the orders of the reaction.

To calculate the rate equation and orders of the reaction I am going to use the log function:

As                Rate [Na2S2O3]x                 and            Rate  [HCL]Y

                 Rate =  k1 × [Na2S2O3]x                                Rate   = k2 × [HCl]Y

Take logs        logRate =  logk1 + X log[Na2S2O3]         logRate =  logk2 + Y log[HCl]

eq. of line             Y   =    C   +  M    X                             Y   =    C   +   M    X

This shows how the power, and order of the reaction, can be found by drawing a graph of logRate against log[concentration] and the gradient of the line will give the order of the reaction. The two equations can then put together to give an overall rate equation:

           

                                Rate =  k × [Na2S2O3]x[HCl]Y

Experimentally I will be changing the concentrations of each the reactants independently and then calculating the rate for each concentration. From these rates I will be able to draw a log graph of rate against concentrations and from my calculation I can find the orders for each of the reactants.

Variables

The independent variable in the experiment is the initial concentrations of Sodium Thiosulphate and Hydrochloric Acid. I will be changing this variable and seeing how it affect the time taken for the reaction to take place and therefore how the concentration affects the rate of the reaction. However as only one variable can be changed I will keep one reactant constant whilst changing the other to get a fair set of results. This will show me the affect of each reactant on the rate independently.

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The dependent variable is the one that will be monitored in the reaction. The dependent variable is the time taken for the reaction to take place which can be used to calculate the rate of the reaction. The method I will be using is by seeing how long it takes for a black cross underneath the conical flask to disappear which will be the point in all the reactions where the concentration of the sulphur precipitate is equal and so will the rate can be fairly calculated. To reduce errors I will need to use my preliminary results to ...

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