Investigate the relationship between temperature and resistance in a thermistor.

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Thermistors Investigation
Aim

To investigate the relationship between temperature and resistance in a thermistor.

Introduction

A current is the flow of charge round a circuit, this can be in the form of ions in a liquid or electrons in a metal.

Resistance is anything that slows the flow of electrons round the circuit.

Ohm's law states that the voltage is equal to the current multiplied by the resistance - V=IR

This can be re-arranged to say R=V/I.

Ohms law states that in a metal component the ratio of voltage to current remain constant, meaning that the resistance stays the same as long as the temperature remains the same. In this experiment I will be changing the temperature therefore this rule will not apply, however the equation R=V/I is always true as it is the way resistance is defined.

In a wire when the temperature is increased the resistance increases. This is because at a higher temperature the lattice atoms are vibrating faster and are colliding with the electrical current and slowing down the flow of charge.

This is also true in a thermistor but there is another competing effect because it is a semiconductor. Being a semiconductor means that the outer electrons are not free at room temperature but when heated the get more energy and are freed. This means that there are more electrons available to conduct. This does not apply in a normal wire because the outer electrons are free and the inner electrons are tightly held in the atom. The two competing effects in the thermistor mean that when the temperature is increased the resistance decreases. If the resistance decreases then the current increases.

Preliminary experiment

In this experiment I measured the current round the circuit when the thermistor was at different temperatures, I heated the water in the beaker and read its temperature with the thermometer. I then measured the current at each 50C interval from room temperature (200C) to 1000C. I did this to see at what temperature I should start my experiment. When the temperature is low the current does not change a lot and because the numbers are such small fractions any errors would be a really high percentage and it would not give me accurate results with the equipment I am using.

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Results


Preliminary Experiment Diagram



These results tell me that when the temperature was increased the current increased and therefore the resistance must decrease (R=V/I)

To calculate the resistance in the next experiment I will also measure the Voltage using a voltmeter. I need to do this because although I am keeping the voltage the same on the power pack this may not be accurate due to the change in resistance round the circuit.

Plan

Apparatus-

Ammeter

Thermistor

Bunsen burner

Tripod

Clamp stand

Clamp

Gauze

Thermometer

Beaker

Water

Power pack

Wires

Crocodile clips

Voltmeter

I will set up the equipment as ...

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